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poizon [28]
2 years ago
6

This is for fun type as many Christmas songs as you can below my fav will get brainiest you will get 18 points as well.

Mathematics
1 answer:
Anika [276]2 years ago
7 0

We wish you a Merry Christmas

Jingle Bells

Mary did you know

Where are you Christmas

Sleigh Ride

Last Christmas

Rocking Around the Christmas tree

Santa Baby

Mistletoe

The Little Drummer Boy

All I want for Christmas is you

Santa Tell me

Peace on Earth

Grandma got ran over by a reindeer

God rest ye merry gentlemen

Little Saint Nick

Underneath the tree

A Merry little Christmas

Do you hear what I hear

Hallelujah

Christmas in the Hollis

We need a little Christmas

Home for Christmas

Oh holy night

Blue Christmas

Silent Night

A Christmas Carol

White Christmas

Feliz Navidad

Charlie Brown Christmas

When a Child was born

Rudolph the rednosed reindeer

We three kings

Santa Claus is coming to town

Carol of the bells

Silver bells

Joy to the world

Angels we have heard on high

Baby it's cold outside

Step-by-step explanation:

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aev [14]

Answer:

53.13⁰

Step-by-step explanation:

Use sine:

sinθ=opposite/hypotenuse

sin∠A=4/5

∠A=sin⁻¹(0.8)=53.13010235415≈53.13⁰

8 0
3 years ago
1. Six units to the left of 3
trapecia [35]

Answer:

six uniys to left of 3 is= +2,+1,0,-1-2-3

three unit right of 15is= +16,+17, +18

Eight unit to the left of =-4,-5,-6,-8,-9,-10,-11,-12

seven units ti right of -5=-3,-2,-1,0+1,+2,+3,+4

8 0
2 years ago
Solve sec2theta + tantheta - 3 =0 for 0
Serhud [2]

Answer:

Ф = \frac{\pi }{4} ,\frac{5\pi}{4}

Step-by-step explanation:

It is a bit difficult to input the work here, so I uploaded an image

  • First we can use the trig identities to change sec²(Ф) to tan²(Ф) + 1
  • Then we can combine like terms
  • Then we can factor this as a polynomial function
  • Then we can set each term equal to zero and solve for Ф
  • The first term tan(Ф) - 2 = 0 has no solution because tan(Ф) ≠ -2 anywhere
  • The second term tan(Ф) - 1 = 0 has two solutions of \frac{\pi}{4} and \frac{5\pi}{4} so these are the solutions to the problem

7 0
3 years ago
It takes 12 hours for a single hose to fill a large vat. When a second hose is added, the vat can be filled in 4 hours. How many
aksik [14]
<h3>Answer:</h3>

6 hours

<h3>Step-by-step explanation:</h3>

The two hoses together take 1/3 the time (4/12 = 1/3), so the two hoses together are equivalent to 3 of the first hose.

That is, the second hose is equivalent to 2 of the first hose. Two of the first hose could fill the vat in half the time one of them can, so 6 hours.

The second hose alone can fill the vat in 6 hours.

_____

The first hose's rate of doing work is ...

... (1 vat)/(12 hours) = (1/12) vat/hour

If h is the second hose's rate of doing work, then working together their rate is ...

... (1/12 vat/hour) + h = (1/4 vat/hour)

... h = (1/4 - 1/12) vat/hour = (3/12 -1/12) vat/hour = 2/12 vat/hour

... h = 1/6 vat/hour

so will take 6 hours to fill 1 vat.

8 0
3 years ago
Matthew bought snacks for soccer team. He bought a bag of apple slices for $5.65, and he bought a 12 pack of Gatorade bottles. T
agasfer [191]

Answer:

6.48/12=B

Step-by-step explanation:

B=6.48

6.48/12=0.54

Each Gatorade bottle costs 54 cents.

5 0
3 years ago
Read 2 more answers
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