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Over [174]
2 years ago
5

What are the zeros for 3x^2 - 17x = -10? Below, you need to choose the correct factors and the correct zeros.

Mathematics
1 answer:
alexandr1967 [171]2 years ago
7 0

Answer:

Step-by-step explanation:

3x²-17x=-10

3x²-17x+10=0

3x²-2x-15x+10=0

x(3x-2)-5(3x-2)=0

(3x-2)(x-5)=0

3x-2=0,x=2/3

x-5=0,x=5

You might be interested in
Divide 12x^4+17^3+8x-40 by x-2
chubhunter [2.5K]

Answer:

12x^3 + 24x^2 + 48x + 104 + (5081/x-2)

Step-by-step explanation:

12x^4 + 17* (17*17) + 8x -40/ x-2

1. remove the parenthesis

12x^4 + !7 * 17 * 17 + 8x -40 / x-2

2. multiply 17 by 17

12x^4 + 289 * 17 + 8x -= 40 /x-2

3. multiply 289 by 17

12x^ = 4913 + 8x - 40 / x-2

4. move 4913

12x^4 + 8x + 4913 - 40 / x-2

5. subtract 40 from 4913

12x^4 + 8x + 4873 / x-2

6. set up polynomials to be divided. if there is not a term for every exponent, insert one with a value of 0

x-2 into 12x^4 + 0x^3 + 0x^2 + 8x + 4873

7. divide the highest order term  in the dividend 12x^4 by the highest order term in divisor x = 12x^3

8. multiply by new quotient term

12x^3 * x-2 = 12x^4 -24x^3

9. the expression needs to be subtracted from the dividend, so change all the signs in 12x^4 - 24x^3

12x^4 + 0x^3 - 12x^4 + 24x^3

10. after changing the signs, add the last dividend from the multiplied polynomial to find new dividend

+24x^3

11.  pull the next term from the original dividend down into the current dividend

+24x^3 + 0x^2

12.  divide the highest order term in the dividend 24x^3 by the highest order term in divisor x = 24x^2

12x^3 + 24x^2

13. multiply new quotient by the divisor

24x^3 * x-2 = 24x^3 - 48x^2

14. the expression needs to be subtracted from the dividend, so change all the signs in 24x^3 - 48x^2

24x^3 + 0x^2 - 24x^3 + 48x^2

15. after changing the signs, add the last dividend from the multiplied polynomial to find new dividend

+48x^2

16. pull the next terms from the original dividend down to the current dividend

+ 48x^2 + 8x

17. divide the highest order term in the dividend 48x^2 by the highest order term in the divisor = 48x

12x^3 + 24x^2 + 48x

18. multiply the new quotient term by the divisor

48x * x - 2 = 48x^2 - 96x

19. the expression needs to be subtracted from the dividend, so change all the signs in 48x^2 - 96x

-48x^2 + 96x

20. after changing the signs, add the last dividend from the multiplied polynomial to find new dividend

48x^2 + 8x - 48x^2 + 96x

= 104x

21. pull the next terms from the original dividend down to the current dividend

+ 104x + 4873

22. divide the highest order term in the dividend 104x by the highest order term in the divisor x = 104

23. divide the new quotient by the divisor

104 * x -2 = 104x - 208

24. the expression needs to be subtracted from the dividend, so change all the signs in 104x - 208

104x + 4873 - 104x + 208 = 5081

25. the final answer is the quotient plus the remainder over the divisor

12x^3 + 24x^2 + 48x + 104 + (5081 / x - 2)

5 0
3 years ago
Please help, I rally need ir
Mnenie [13.5K]

Answer:

The one on the top at you’re right

3 0
2 years ago
Which expressions is equivalent to (x+2)(3x-3)
max2010maxim [7]

Answer:

Step-by-step explanation:

(x+2)(3x-3)

= 3x^2 -3x + 6x - 6

= 3x^2 + 3x - 6

6 0
2 years ago
The ordered pair (-4, -5) is a solution of the following system of equations 2x+y=13 19x+13y=15
liberstina [14]

Answer:

Step-by-step explanation

672

8 0
2 years ago
At a local election there were two propositions on the ballot, R and S. Twice as many voters voted "yes" for R as for S. If the
Over [174]

Answer:

c. 130

Step-by-step explanation:

Let call B the quantity of voters who voted yes for both propositions.

From the question we know that twice as many voters voted "yes" for R as for S, that can be written as the following equation:

R+B=2(S+B)

Where R is the number who voted "yes" for R but "no2 for S and S is the number who voted "yes" for S but "no" for R.

Replacing R by 750 and S by 310 and solving for B, we get:

750+B=2(310+B)

750+B=620+2B

2B-B=750-620

B=130

So, 130 voters voted yes for both propositions

7 0
3 years ago
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