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larisa86 [58]
3 years ago
9

A 4.3 ounce tomato has about 24 calories how many calories are in one ounce

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
3 0
Divide.

What is 24 / 4.3? 
It is 5.58(Rounded)
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Please help!!!
WINSTONCH [101]

Answer:

14

Step-by-step explanation:

2(l+b)

2(3+4)

2(7) now do multiply

answer 14m

6 0
3 years ago
accounting theories are the foundation for understanding your company's financial direction and developing strategies for long t
scoray [572]

Accounting theories give an idea of ​​how to do it, how to follow it and the corresponding methodology, therefore the owner of a company must recognize these accounting theories to comply within the company.

We have the following accounting theories:

Comparable: It must be presented in a way, which may be compared thoroughly. Such as sales increased by way of 10% from the closing yr.

Relevant: Accounting information ought to be relevant; such as contemporary yr’s records with relevant facts have to be presented in economic report.

Consistent: Methods applied in accounting ought to be consistent; assume immediately line technique of charging depreciation is accompanied since last 5 years. If such technique is converting heavily, like instantly-line for this year and double declining technique inside the coming yr, then the system isn't regular and it doesn’t indicate smooth accounting.

Reliable: There should be reliability; such as coins bills are supported by way of respective vouchers of coins disbursements.

8 0
3 years ago
X/2 = Y/3 = Z/4. prove that :2X-Y+5Z / 3Y-X =3. note :: (/) is for a fraction aka divide. help pls I've been stuck on it for a f
sweet-ann [11.9K]

The given equation

x/2 = y/3 = z/4

can be broken into three separate equations which I'll call equations (A), (B) and (C)

  • x/2 = y/3 ..... equation (A)
  • y/3 = z/4 .... equation (B)
  • x/2 = z/4 .... equation (C)

We'll start off solving for z in equation (C)

x/2 = z/4

4x = 2z ... cross multiply

2z = 4x

z = 4x/2 ... divide both sides by 2

z = 2x

Now let's solve for y in equation (A)

x/2 = y/3

3x = 2y

2y = 3x

y = 3x/2

y = (3/2)x

y = 1.5x

The results of z = 2x and y = 1.5x both have the right hand sides in terms of x. This will allow us to replace the variables y and z with something in terms of x, which means we'll have some overall expression with x only. The idea is that expression should simplify to 3 if we played our cards right.

We won't be using equation (B) at all.

---------------------

The key takeaway from the last section is that

  • z = 2x
  • y = 1.5x

Let's plug those items into the expression (2x-y+5z)/(3y-x) to get the following:

(2x-y+5z)/(3y-x)

(2x-y+5(2x))/(3y-x) ..... plug in z = 2x

(2x-y+10x)/(3y-x)

(12x-y)/(3y-x)

(12x-1.5x)/(3(1.5x)-x) .... plug in y = 1.5x

(12x-1.5x)/(4.5x-x)

(10.5x)/(3.5x)

(10.5)/(3.5)

3

We've shown that plugging z = 2x and y = 1.5x into the expression above simplifies to 3. Therefore, the equation (2x-y+5z)/(3y-x) = 3 is true when x/2 = y/3 = z/4. This concludes the proof.

5 0
3 years ago
Kaya had a string 6 1/8 inches long. She cut off a piece 2 3/4 inches long. How long is the remaining piece of string? Show your
Katen [24]

Answer: 3 3/8

Step-by-step explanation:

We know that for example 2/4=4/8 so it is multiplied by 2. In this problem the fractions are 2 2/4 and 6 1/8. We are subtracting so you would first multiply the fraction that’s going to subtracted from the other fraction 2 3/4= 2 6/8. Now that we have our fractions we can subtract 6 1/8-2 6/8 this would leave us with 3.375 which is equal to 3 3/8.

4 0
3 years ago
Read 2 more answers
Two fair coins are flipped. Given that at least one coin lands on a head, calculate the probability of one head and one tail. Wr
Greeley [361]

The probability of one head and one tail is 2/3.

<u>Step-by-step explanation</u>:

  • The possibilities for flipping two fair coins are {T,T}, {H,H}, {H,T}, {T,H}
  • Given the case that at least one coin lands on a head, So the total possibilities are {H,H}, {H,T}, {T,H} = 3 possibilities
  • Required event is 1 head and 1 tail= {H,T}, {T,H} = 2 possibilities

To calculate the probability of one head and one tail,

Probability = required events / Total events

Probability = 2/3

8 0
3 years ago
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