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Y_Kistochka [10]
3 years ago
10

So explain this with the answer 14v+6 please

Mathematics
2 answers:
Nikitich [7]3 years ago
5 0

Answer:

2(7v+3)

Step-by-step explanation:

Factoring

Rashid [163]3 years ago
5 0
Distribute property use a Calculator it will show you steps
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J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.
melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

                      P.Q.  =  \frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }  ~ t__n_1_+_n_2_-_2

where, \bar X_1 = sample mean for mail-order sales = $74.50

\bar X_2 = sample mean for internet sales = $84.40

s_1 = sample standard deviation for mail-order purchases = $17.25

s_2 = sample standard deviation for internet purchases = $21.25

n_1 = sample of sales receipts for mail-order purchases = 16

n_2 = sample of sales receipts for internet purchases = 9

Also,  s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }  =  \sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} } = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by (\mu_1-\mu_2).

Now, 99% confidence interval for (\mu_1-\mu_2) is given by;

             = (\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_)  \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

          = (74.50-84.40) \pm (2.807  \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})

          = [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0
3 years ago
2.What solid figure is described by a water hose?
expeople1 [14]

Answer:

cylinder <3

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A fair coin is flipped 10 times and lands on heads 8 times. Provide a reason to justify the difference between the experimental
professor190 [17]

Answer:

THere will be 8 heads and 2 tails

Step-by-step explanation:

I don't know

5 0
3 years ago
The liquid volume of Eric's water bottle is 3 liters. What is the approximate liquid volume of 5 of these bottles in milliliters
stepan [7]

Answer:

Option D is correct

The approximate liquid volume of 5 of these bottles is, 15,000 milliliters.

Step-by-step explanation:

Given the statement: The liquid volume of Eric's water bottle is 3 liters.

Using conversion:

1 liters = 1000 milliliters

Convert 3 liters into milliliters;

using above conversion:

3 liters  = 3 \times 1000 = 3000 milliliters.

To find the volume of liquid in 5 of these bottles in milliliters:

Volume of liquid in 1 bottle is, 3000 milliliters.

then;

Volume of liquid in 5 bottles  = 5 \times 3000 = 15,000 milliliters.

Therefore, approximate liquid volume of 5 of these bottles is, 15,000 milliliters

6 0
3 years ago
Does anyone need my help on anything that isnt math right now?​
dexar [7]

Answer: you can change the subject so that you can help people with other subjects

Step-by-step explanation:

8 0
3 years ago
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