Please help!! this is the question right here

Mathematics

1 answer:

Sidana [21]3 years ago

6 0

John is correct because between the time and distance, you divide by 9 to get the distance or multiply by 9 to get the time.

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Twenty six thousandths in numerical form

Andrew [12]

Answer:

0.026

Step-by-step explanation:

Twenty-Six = 26 ( But for simplicity in the Next Step write it as 26.)

Tenths means to move the Decimal Point 1 Place Left
Hundredths means to move the Decimal Point 2 Place Left
Thousandths means to move the Decimal Point 3 Place Left

Then Twenty-Six Thousandths = 0.026

8 0

2 years ago

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a group of students attend a math club half the students are boys and 4/9 of the boys have brown eyes what fraction of the group

enyata [817]

From the whole group half the club are boys.
fraction of boys from the whole class = 1/2
from this fraction, 4/9th of the boys have brown eyes
therefore fraction of boys who have brown eyes
= 4/9 of 1/2
the 'of' function is used to multiply
$\frac{4}{9} * \frac{1}{2}$
when multiplying fractions numerators are multiplied by numerators and denominators multiplied by denominators
$\frac{4*1}{9*2} = \frac{4}{18}$
4/18 can be simplified by dividing the whole number by a common number
4/18 divided by 2 = 2/9
the answer is 2/9
2/9 of the club are boys with brown eyes

3 0

3 years ago

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Find the real numbers x and y if -3+ix^2y and x^2+y+4i are conjugate of each other. Pls solve with the steps

Firdavs [7]

ANSWER
x = ±1 and y = -4.
Either x = +1 or x = -1 will work

EXPLANATION
If -3 + ix²y and x² + y + 4i are complex conjugates, then one of them can be written in the form a + bi and the other in the form a - bi. In other words, between conjugates, the imaginary parts are same in absolute value but different in sign (b and -b). The real parts are the same

For -3 + ix²y
⇒ real part: -3
⇒ imaginary part: x²y

For x² + y + 4i
⇒ real part: x² + y (since x, y are real numbers)
⇒ imaginary part: 4

Therefore, for the two expressions to be conjugates, we must satisfy the two conditions.

Condition 1: Imaginary parts are same in absolute value but different in sign. We can set the imaginary part of -3 + ix²y to be the negative imaginary part of x² + y + 4i so that the

x²y = -4 ... (I)

Condition 2: Real parts are the same

x² + y = -3 ... (II)

We have a system of equations since both conditions must be satisfied

x²y = -4 ... (I)
x² + y = -3 ... (II)

We can rearrange equation (II) so that we have

y = -3 - x² ... (II)

Substituting into equation (I)

x²y = -4 ... (I)
x²(-3 - x²) = -4
-3x² - x⁴ = -4
x⁴ + 3x² - 4 = 0
(x² + 4)(x² - 1) = 0
(x² + 4)(x-1)(x+1) = 0

Therefore, x = ±1.
Leave alone (x² + 4) as it gives no real solutions.

Solve for y:

y = -3 - x² ... (II)
y = -3 - (±1)²
y = -3 - 1
y = -4

So x = ±1 and y = -4. We can confirm this results in conjugates by substituting into the expressions:

-3 + ix²y
= -3 + i(±1)²(-4)
= -3 - 4i

x² + y + 4i
= (±1)² - 4 + 4i
= 1 - 4 + 4i
= -3 + 4i

They result in conjugates

4 0

3 years ago

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How to covert 11 pi over 12 to degrees

Readme [11.4K]

When you convert 11pi over 12 in to degrees, you get 165°

4 0

3 years ago

The angles of elevation froma point X to the top of flagpoles A and B are 35* and 45* respectively. If X lies in the middle of t

BartSMP [9]

Let AB = t. And since X lies in the middle, so AX=BX = t/2 .

Let the height of the smaller flagpole is AO and of larger flagpole is BP .