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GarryVolchara [31]
3 years ago
10

What is the quotient 5/7 ÷ 3 1/3​

Mathematics
1 answer:
snow_lady [41]3 years ago
5 0

Answer: 3/14

Step-by-step explanation:

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Hailey is a high school basketball player. In a particular game, she made some three point shots and some free throws (worth one
NISA [10]

Answer: the system of equations are

3x + y = 14

y = 4x

Step-by-step explanation:

Let x represent the number of three point shots that Hailey made.

Let y represent the number of free throws(worth one point each) that Hailey made.

Hailey made some three point shots and some free throws and

scored a total of 14 points. This would be expressed as

3x + y = 14

Hailey made 4 times as many free throws as three point shots. This would be expressed as

y = 4x

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3 years ago
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What’s the area for each of these figures
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Step-by-step explanation:

you should try multiplying all the sides and don't forget that a triangle is base times height and divided by two

 

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3 years ago
Select all the sentences that correctly identify the components of the experiment.
lesya [120]

Answer:

A,D,E,F

Step-by-step explanation:

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Aikong spent 3/8 of his time studying Science. He spent 2/5 as much time studying English as Science. WHAT fraction of Aikong's
seraphim [82]

Time spent by Aikong in studying English = \frac{2}{5} as much time in studying Science

Time taken in studying Science = \frac{3}{8} of his time

Time spent by Aikong in studying English = \frac{2}{5} of \frac{3}{8}

= \frac{2}{5} \times \frac{3}{8}

=\frac{6}{40}

Reducing it to the lowest term.

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5 0
3 years ago
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if h=-16t ²+160t represents the height of a rocket in T seconds after it was fired when will the rocket hit the ground?
makkiz [27]

Answer:

The time after which the rocket hit the ground is 5 seconds

Step-by-step explanation:

Given as :

The distance of the cover by rocket at the height h = - 16 t² + 160 t

Let the time after which rocket hit the ground = T seconds

Now, When the rocket hits the ground, then at that time, the velocity of the rocket becomes zero.

I.e velocity = \frac{\partial h}{\partial t} = 0

Or, v = \frac{\partial h}{\partial t} = 0

Now, v = \frac{\partial h}{\partial t}

Or, v = \frac{\partial (-16t^{2}+160t)}{\partial t}

or, v = - 32 t + 160

Now, ∵ velocity of rocket after reaching the ground becomes zero

So, v = - 32 t + 160 = 0

Or, 32 t = 160

Or, t = \frac{160}{32}

∴ t = 5 sec

So, The time after which the rocket hit the ground = 5 sec

Hence The time after which the rocket hit the ground is 5 seconds answer

6 0
3 years ago
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