All categories

2 years ago

Evaluate: f(x) = 2x^2 + 6x - 4; f(-5) *

Mathematics

2 answers:

jasenka [17]2 years ago

8 0

$f(x)=2x^2+6x-4\\$

Find f(-5) by substituting x = -5 in the equation.

$f(-5)=2(-5)^2+6(-5)-4\\f(-5)=2(25)-30-4\\f(-5)=50-34\\f(-5)=16$

Therefore, the answer is f(-5) = 16

grin007 [14]2 years ago

3 0

Answer:

f(-5)=126

Step-by-step explanation:

what you would do first is plug -5 in for x which would give you the equation of f(-5)= 2(-5)^2 + 6(-5) -4

then you multiply the negative 5 and you will get

f(-5)= -10^2 + 30 -4

remove that square by multiplying -10 by -10 and you will get

f(-5)= 100 + 30 -4

combine like terms and you will get

f(-5)=126

i hope this helped you and that i explained it to you in a way that you understand

You might be interested in

Please help!! <br>if you can explain if not that is fine.<br>

Scorpion4ik [409]

Answer:

The graph of y > 3x − 4 has shading above a dashed line.

The graphs of the inequalities will intersect.

6 0

3 years ago

There are 30 nonfiction books and 34 fiction books in the teachers collection. Which of the following expresses the ratio of fic

Yanka [14]

Divide each by 2 and you get 15:16

3 0

3 years ago

How many computers must the AB Computer Company sell to break even? Let x be the number of computers.

Eduardwww [97]

Answer:

The Company AB must sell 116 computers to break even

Step-by-step explanation:

we have

$R(x)=1.5x$ -----> equation A

$C(x)=145+\frac{1}{4}x$ ----> equation B

where

C is the cost function

R is the revenue function

x is the number of computers sold

we know that

Break even is when the cost is equal to the revenue

equate equation A and equation B

$1.5x=145+\frac{1}{4}x$

Solve for x

subtract 1/4x both sides

$1.5x-\frac{1}{4}x=145$

$1.5x-0.25x=145$

$1.25x=145$

Divide by 1.25 both sides

$x=116$

therefore

The Company AB must sell 116 computers to break even

7 0

3 years ago

HELP ASAP. please show work tysm! solve for x

nata0808 [166]

Answer:

Step-by-step explanation:

vertical sides are congruent

x+30=101

x=71

7 0

3 years ago

The length of a rectangle is eight more than twice its width. The perimeter is 96 feet. Find the dimensions of the rectangle

Debora [2.8K]

Answer:

The width of the rectangle is 14'8", and the length is 33'4"

Step-by-step explanation:

We're given two pieces of information:

The length is eight more than twice the width:

$l = 2w + 4$

The perimeter is 96 feet:

$p = 96$

We also need to apply one more piece of information that is not provided here, and that is the relationship between the perimeter of a rectangle, and it's length and width:

$p = 2l + 2w$

We can solve for w by plugging the other two values into the last:

$p = 2w + 2l\\96 = 2w + 2(2w + 4)\\96 = 2w + 4w + 8\\88 = 6w\\3w = 44\\w = \frac{44}{3}\\w = 14\frac{2}{3}$

Now we can find the length by plugging w into the first equation:

$l = 2w + 4\\l = 2(14\frac{2}{3}) + 4\\l = 29\frac{1}{3} + 4\\l = 33\frac{1}{3}$

One third of a foot is four inches, so the width is 14'8" and the length is 33'4"

To make sure our answer is correct, we should plug those numbers back into the area equation and see if we're right:

$p = 2l + 2w\\p = 2(33\frac{1}{3}) + 2(14\frac{2}{3})\\p = 66\frac{2}{3} + 29\frac{1}{3}\\p = 96$

So we know our answer's correct

8 0

2 years ago