We keep the 2x^2 because we can only subtract something from that if it also is squared. From there, we subtract the 7x from 2x^2-11. Since there is no previous x's in the 2x^2-11, we just make it -7x. So, without even continuing the problem, we see that A) is the correct answer because it is the only one with -7x.
Answer:
<em>Bree spoke at 55 assemblies in this district.</em>
Step-by-step explanation:
Bree speaks at school assemblies charging a school district a total cost C modeled by the equation:
C(a) = 50a+1,500
Being a the number of assemblies attending the meeting.
It's given Bree charged the Escambia City School District $4,250 to speak at school assemblies.
We can find the number of assemblies by solving the equation:
50a+1,500=4,250
Subtracting 1,500:
50a=4,250-1,500=2,750
Dividing by 50;
a = 2,750 / 50=55
Bree spoke at 55 assemblies in this district.
◆ COMPLEX NUMBERS ◆
125 ( cos 288 + i sin 288 ) can be written as -
125.e^i( 288)
125.e^i( 288 +360 )
125.e^i( 288+ 720)
[ As , multiples of 360 can be added to an angle without changing any trigonometric functions or sign ]
To find the cube root , take the cube root of above 3 expressions ,
We get -
5 e^( i 96 )
5 e^( i 216 )
5 e^( i 336 )
Now using Euler's formula , We rewrite above as -
5 ( cos 96 + i sin 96 )
5(c os 216 + i sin 216 )
5 ( cos 336 + i sin 336 ) Ans.
Call x is the number of girls in the classroom.
12/120 = 25/x
x = 120*25/12
x=250
Answer 250 girsl
