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shepuryov [24]
3 years ago
5

HELP ME PLEASE!!!!!!

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
3 0
THE ANSWER FOR THIS IS G. 16
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Check for Understanding_Compare and Order Rational Numbers
Morgarella [4.7K]

The methods for comparing rational numbers include:

  • Cross-multiply and compare the products.
  • Convert both fractions to fractions with a common denominator.
  • Turn both fractions into decimals by dividing.

<h3>What is a rational number?</h3>

It should be noted that a rational number is a number that is expressed as the ratio of two integers, where the denominator should not be equal to zero.

Rational numbers are terminating decimals while irrational numbers are non-terminating and non-recurring.

Learn more about numbers on:

brainly.com/question/24368848

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7 0
1 year ago
Bad gums may mean a bad heart. Researchers discovered that 79% of people who have suffered a heart attack had periodontal diseas
zysi [14]

Answer:

(A) 0.297

(B) 0.595

Step-by-step explanation:

Let,

H = a person who suffered from a heart attack

G = a person has the periodontal disease.

Given:

P (G|H) = 0.79, P(G|H') = 0.33 and P (H) = 0.15

Compute the probability that a person has the periodontal disease as follows:

P(G)=P(G|H)P(H)+P(G|H')P(H')\\=P(G|H)P(H)+P(G|H')(1-P(H))\\=(0.79\times0.15)+(0.33\times(1-0.15))\\=0.399

(A)

The probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is:

P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.15}{0.399} \\=0.29699\\\approx0.297

Thus, the probability that a person had periodontal disease, what is the probability that he or she will have a heart attack is 0.297.

(B)

Now if the probability of a person having a heart attack is, P (H) = 0.38.

Compute the probability that a person has the periodontal disease as follows:

P(G)=P(G|H)P(H)+P(G|H')P(H')\\=P(G|H)P(H)+P(G|H')(1-P(H))\\=(0.79\times0.38)+(0.33\times(1-0.38))\\=0.5048

Compute the probability of a person having a heart attack given that he or she has the disease:

P(H|G)=\frac{P(G|H)P(H)}{P(G)}\\=\frac{0.79\times0.38}{0.5048}\\ =0.59469\\\approx0.595

The probability of a person having a heart attack given that he or she has the disease is 0.595.

4 0
3 years ago
3х +5 &gt; – 2x — 5<br> ............
Yanka [14]

Answer:

x>-2

Step-by-step explanation:

6 0
3 years ago
Whats the distance between the points (7,3) and (7,-8)?
Basile [38]
11. The negative 8 had to go to the positive 3. You add 8 automatically to get yourself to 0. Once you do that you add three to make them the same to find the distance. The answer is 11.
5 0
3 years ago
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Pleasee help ill give brainliest
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B or Always increasing
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2 years ago
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