HELP ME PLEASE!!!!!!

4 times x with an exponent of 2 plus 2 times y with an exponent of 4. X=-3 y=2

Digiron [165]

Answer:

Step-by-step explanation:

Your equation is: $4*x^{2} +2 * y^{4}$

You also know that x = -3 and y = 2. You can rewrite the equation by substituting x and y with their actual values:

$4*(-3)^{2} +2 * 2^{4}$

First, you want to do the exponentiation (meaning you want to calculate $(-3)^{2}$ and $2^{4}$ parts). $(-3)^{2}$ equals 9 and $2^{4}$ equals 16.

So the equation now is:

$4*9+2*16$

Now you want to do multiplication. $4*9$ equals 36 and $2*16$ equals 32. So you're left with:

$36+32$

Which equals 68.

8 0

3 years ago

0.6x = 31.2 ( it's multiplication)

Rasek [7]

X = 52 would be the answer you get.

Explanation you would divide both sides by 0.6 which leaves the x and by dividing 31.2 divided by 0.6 it gives you 52

8 0

3 years ago

A study of a new medical procedure selected 27 candidates from a pool of 583 potential candidates.Each of the candidates had an

nikklg [1K]

The answer is random sampling

7 0

3 years ago

Can someone plz help me with this!

asambeis [7]

Answer:

(arranged from top to bottom)

System #3, where x=6

System #1, where x=4

System #7, where x=3

System #5, where x=2

System #2, where x=1

Step-by-step explanation:

System #1: x=4

$2x+y=10\\x-3y=-2$

To solve, start by isolating your first equation for y.

$2x+y=10\\y=-2x+10$

Now, plug this value of y into your second equation.

$x-3(-2x+10)=-2\\x+6x-30=-2\\7x=28\\x=4$

System #2: x=1

$x+2y=5\\2x+y=4$

Isolate your second equation for y.

$2x+y=4\\y=-2x+4$

Plug this value of y into your first equation.

$x+2(-2x+4)=5\\x+(-4x)+8=5\\x-4x+8=5\\-3x=-3\\x=1$

System #3: x=6

$5x+y=33\\x=18-4y$

Isolate your first equation for y.

$5x+y=33\\y=-5x+33$

Plug this value of y into your second equation.

$x=18-4(-5x+33)\\x=18+20x-132\\-19x=-114\\x=6$

System #4: all real numbers (not included in your diagram)

$y=13-2x\\8x+4y=52$

Plug your value of y into your second equation.

$8x+4(13-2x)=52\\8x+52-8x=52\\0=0$

<em>all real numbers are solutions</em>

System #5: x=2

$x+3y=5\\6x-y=11$

Isolate your second equation for y.

$6x-y=11\\-y=-6x+11\\y=6x-11$

Plug in your value of y to your first equation.

$x+3(6x-11)=5\\x+18x-33=5\\19x=38\\x=2$

System #6: no solution (not included in your diagram)

$2x+y=10\\-6x-3y=-2$

Isolate your first equation for y.

$2x+y=10\\y=-2x+10$

Plug your value of y into your second equation.

$-6x-3(-2x+10)=-2\\-6x+6x-30=-2\\-30=-2$

<em>no solution</em>

System #7: x=3

$y=10+x\\2x+3y=45$

Plug your value of y into your second equation.

$2x+3(10+x)=45\\2x+30+3x=45\\5x=15\\x=3$

3 0

3 years ago

I WILL GIVE BRAINLIEST TO WHOEVER ANSWERS GOOD PLEASE

12345 [234]

Answer:

Figure 1

Step-by-step explanation:

Congruent shapes are shapes that share the same side lengths and angle measures. In figure 1, we see that all sides and angles are marked equal, thus both shapes are congruent. However, in figure 2, we clearly see that the sides of each of the triangles are different. Thus, the triangles in figure 2 are not congruent.

4 0

3 years ago

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