Answer:

Step-by-step explanation:
Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin)
.
We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63
b = ±√(a² - c²)
= ±√(91² - 63²)
= ±√(8281 - 3969)
= ±√4312
= ±14√22
So the equation is

Answer:
4y = 2
Step-by-step explanation:
9y + 5 = 7 + 3y + 2y
9y-2y-3y=7-5
4y=2
Pretty sure it’s “b= p/2 - a” which is the second answer
Answer:
The equation is y = 2x + 11.
Step-by-step explanation:
It is given that the gradient of the equation is 2. Using slope-form formula, y = mx+b where m is gradient and b is y-intercept. In order to find b, you have to substitute x-coordinate and y-coordinate into the equation :
y = mx + b
m = 2
At(-4,3),
3 = 2(-4) + b
b = 3 - 2(-4)
= 11
The answer is p , merry Christmas