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2 answers:
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Answer:
a) The probability that a box containing 3 defectives will be shipped is
b) The probability that a box containing only 1 defective will be sent back for screening is
Step-by-step explanation:
Hi
a) The first step is to count the number of total possible random sets of taking a sample size of 4 items over 23 items of the box, so
The second step is to count the number of total possible random sets of taking a sample size of 4 items over 20 items of the box (discounting the 3 defectives) as the possible ways to succeed, so
Finally we need to compute , therefore the probability that a box containing 3 defectives will be shipped is
a) The first step is to count the number of total possible random sets of taking a sample size of 4 items over 23 items of the box, so
The second step is to count the number of total possible random sets of taking a sample size of 4 items over 22 items of the box (discounting the defective 1) as the possible ways to succeed, so
Then we need to compute , therefore the probability that a box containing 1 defective will be shipped is
Finally the probability that a box containing only 1 defective will be sent back for screening will be
8.) Area= 22 squared, Perimeter= 26
9.) Area= 44 squared, Perimeter= 30
9.) Area= 44 squared, Perimeter= 30