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julsineya [31]
3 years ago
15

If the measure of the exterior angle adjacent to the vertex angle of an isosceles triangle is 105 degrees find the measure of th

e base angle
Mathematics
1 answer:
Nina [5.8K]3 years ago
3 0

Given:

The measure of the exterior angle adjacent to the vertex angle of an isosceles triangle is 105 degrees.

To find:

The measure of the base angle.

Solution:

We know that the base angles of an isosceles triangle are equal.

Exterior angle theorem: In a triangle, the sum of two interior angles of the triangle is equal to the opposite exterior angle.

Let x be the measure of the base angle. Then the other base angle is also x.

Sum of base angles = x + x

                                 = 2x

Using exterior angle theorem,

Sum of base angles = Measure of the exterior angle adjacent to the vertex

2x=105^\circ

x=\dfrac{105^\circ}{2}

x=52.5^\circ

Therefore, the measure of the base angle is equal to 52.5 degrees.

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What is X squared +3x-70
Aleksandr-060686 [28]

Answer:

x = 7, x = -10

Step-by-step explanation:

x^2+3x-70 = 0

Use the quadratic formula.

x = \frac{-3 + \sqrt{3^2-4(1)(-70)} }{2(1)} \\x = \frac{-3 - \sqrt{3^2-4(1)(-70)} }{2(1)} \\

Solve.

x = 7, x = -10

You can also factor if you want - that is a faster method.

8 0
4 years ago
Graph the line with slope – 2 passing through the point (-5,5).
34kurt

Answer:

y = -2x - 5

Step-by-step explanation:

y = -2x + b

- To find the y-intercept, plug the values of the variables.

5 = -2(-5) + b

5 = 10 + b

- Subtract 10 from both sides.

-5 = b

3 0
3 years ago
How many lines of symmetry does this figure have?
Sergeeva-Olga [200]

Answer:

2

Step-by-step explanation:

There are two lines of symmetry and here I list them:

1) The first is a horizontal line that divides the square in to even parts such that the top part is the projection of the down one trough the symmetry line (and vice versa).

2) The second one is the vertical line that divides the square in two even sides. Note that this line will also divide both stars at half. The left side will be projected on the right one (and vice versa) trough the symmetry line.

A third line could be thought to be a diagonal between opposite vertices, but notice that the stars projection won't by symmetric in this case.

So, we only have 2 symmetry lines.

4 0
3 years ago
The school that Brenda goes to is selling tickets to the annual talent show. On the first day of the ticket sales the school sol
KiRa [710]
A=cost er adult ticket
c=cost per child ticket

2a+14c=96
12a+8c=120

solve

simplify by dividing firs equation by 2 and 2nd by 4

a+7c=48
3a+2c=30

multiply first equaiton by -3 and add to second
-3a-21c=-144
<u>3a+2c=30 +</u>
0a-19c=-114

-19c=-114
divide both sides by -19
x=6

sub back

a+7c=48
6+7c=48
minus 6
7c=42
divide 7
c=6

adult ticket=$6
child ticekt=$6
7 0
3 years ago
What is the answer, step by step? 208x13
Nostrana [21]

Answer:

208*13= 2704

Step-by-step explanation

    +2

   208

<u> x     13</u>

    624

<u>+ 2080</u>

  2704

6 0
3 years ago
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