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Nesterboy [21]
3 years ago
14

David assembles 12 circuit boards in 255 minutes. Amy assembles 9 circuit boards in 170 minutes. Who works at a faster rate?

Mathematics
2 answers:
Artyom0805 [142]3 years ago
4 0
I think Amy works at a faster rate.
Marat540 [252]3 years ago
4 0
It would be Amy, because Amy does about 18.8 boards per min and David does about 18.75 boards per min.
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Answer: DEFG is a parallelogram

Explanation:
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2 years ago
Which is the graph of the line LaTeX: y-2=3\left(x-1\right)y − 2 = 3 ( x − 1 )?
andreyandreev [35.5K]

Answer:

D.

Step-by-step explanation:

The equation given takes the point-slope form which is, y - b = m(x - a). Where,

(a, b) = (x, y) coordinates of a point on the line.

m = slope of the line .

To find which graph has a line equation of y - 2 = 3(x - 1), look for the points which will give you something almost exactly as the equation if you substitute their values into y - b = m(x - a).

Let's consider option D.

We have a given point (1, 2). a = 1, b = 2.

Substitute these into y - b = m(x - a)

We have:

y - (2) = m(x - (1))

y - 2 = m(x - 1)

As you can see, this looks almost exactly as

y - 2 = 3(x - 1).

If you want to be certain that option D is the answer, find m by using the coordinates of any other point on the line and plug into y - 2 = m(x - 1) to find m:

In graph D, let's take the points (0, -1)

-1 - 2 = m(0 - 1)

-3 = m(-1)

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3 = m

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3 0
3 years ago
Please help! It’s Saturday and I only have this question left on my digital worksheet!
Natalija [7]

Answer:

<h2>The answer is option C</h2>

Step-by-step explanation:

<h3>\frac{ {6}^{ - 3} }{ {6}^{5} }</h3>

Using the rules of indices

Since the bases are the same and are dividing we subtract the exponents

That's

<h3>\frac{ {a}^{x} }{ {a}^{y} }  =  {a}^{x - y}</h3>

So we have

<h3>\frac{ {6}^{ - 3} }{ {6}^{5} }  =  {6}^{ -  3 - 5}  =  {6}^{ - 8}</h3>

Using the rules of indices

<h3>{x}^{ - y}  =  \frac{1}{ {x}^{y} }</h3>

So we have the final answer as

<h2>\frac{1}{ {6}^{8} }</h2>

Hope this helps you

4 0
3 years ago
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