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Lunna [17]
3 years ago
9

What is 45 percent of 37? 0.1665 1.665 16.65 166.5

Mathematics
2 answers:
Leno4ka [110]3 years ago
5 0

Answer:

is it 16.65????

Step-by-step explanation:

lol i took the testtt

xxTIMURxx [149]3 years ago
3 0

Answer:

16.65

Step-by-step explanation:

37 * 0.45 = 16.65

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3y=11-2x, 3x=y-11 linear equation solve using the algebraic method check solution
tamaranim1 [39]

Answer:

(x, y) = (- 2, 5)

Step-by-step explanation:

given the 2 equations

3y = 11 - 2x → (1)

3x = y - 11 → (2)

Rearrange (2) expressing y in terms of x

add 11 to both sides

y = 3x + 11 → (3)

Substitute y = 3x + 11 into (1)

3(3x + 11) = 11 - 2x

9x + 33 = 11 - 2x ( add 2x to both sides )

11x + 33 = 11 ( subtract 33 from both sides )

11x = - 22 ( divide both sides by 11 )

x = - 2

Substitute x = - 2 in (3) for corresponding value of y

y = (3 × - 2) + 11 = - 6 + 11 = 5

As a check

substitute x = - 2, y = 5 into (1) and (2) and if the left side equals the right side then these values are the solution.

(1) :  left side = (3 × 5) = 15

right side = 11 - (2 × - 2) = 11 + 4 = 15 ⇒ left = right

(2) : left side = (3 × - 2 ) = - 6

right side = 5 - 11 = - 6 ⇒ left = right

solution = (- 2, 5 )



5 0
3 years ago
David has a hose that is 27 ft long. He wants to cut it into two pieces so that the longer piece is 3 ft more than 2 times the l
evablogger [386]
One piece is 8ft and the other is 19ft

4 0
3 years ago
Read 2 more answers
In a certain community, 30% of the families own a dog, and 20% of the families that own a dog also own a cat. It is also known t
Komok [63]

Answer:

What is the probability that a randomly selected family owns a cat? 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat? 82.4%

Step-by-step explanation: We can use a Venn (attached) diagram to describe this situation:

Imagine a community of 100 families (we can assum a number, because in the end, it does not matter)

So, 30% of the families own a dog = .30*100 = 30

20% of the families that own a dog also own a cat = 0.2*30 = 6

34% of all the families own a cat = 0.34*100 = 34

Dogs and cats: 6

Only dogs: 30 - 6 = 24

Only cats: 34 - 6 = 28

Not cat and dogs: 24+6+28 = 58; 100 - 58 = 42

What is the probability that a randomly selected family owns a cat?

34/100 = 34%

What is the conditional probability that a randomly selected family doesn't own a dog given that it owns a cat?

A = doesn't own a dog

B = owns a cat

P(A|B) = P(A∩B)/P(B) = 28/34 = 82.4%

5 0
3 years ago
Read 2 more answers
Can someone please explain this to me?
gladu [14]

the circumference is the perimeter of a circle or ellipse. That is, the circumference would be the arc length of the circle.

8 0
3 years ago
X = ????????? Geometry
bazaltina [42]

Answer:

\boxed{x = 6}

Step-by-step explanation:

Using Chord-Chord Power theorem:

=> (2)(x) = (4)(3)

=> 2x = 12

Dividing both sides by 2

=> x = 6

7 0
3 years ago
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