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3 years ago

Can somebody help me please!

Mathematics

1 answer:

Nina [5.8K]3 years ago

3 0

1. $3.99 for 16 ounces
= $399/(16 ounces) = $0.25 per ounce
Answer: $0.25 per ounce

2. 730 miles in 14 hours
= (730 miles)/(14 hours) = 52 mph
Answer: 52 mph

3. $28 for 15 goldfish
= ($28)/(15 goldfish) = $1.87 per goldfish
Answer: $1.87 per goldfish

4. 234 calories in 3 servings
= (234 calores)/(3 servings) = 78 calories per serving
Answer: 78 calores per serving

5. $1.99 for a 3-ounce bottle = $1.99/3 = $0.66 per ounce.
$2.49 per a 4-ounce bottle = $2.49/4 = $0.62 per ounce.
The better price is $2.49 per a 4-ounce bottle.
Answer: $2.49 per a 4-ounce bottle

6. Distance traveled = 424 miles.
Time of travel = 8 hours.
Rate of travel = (424 miles)/(8 hours) = 53 mph
Answer: B. 53

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4 years ago

Someone please help me

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<h3>Answer:</h3>

C. (9x -1)(x +4) = 9x² +35x -4
B. 480
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Step-by-step explanation:

1. See the attachment for the filled-in diagram. Adding the contents of the figure gives the sum at the bottom, matching selection C.

2. If we let "d" represent the length of the second volyage, then the total length of the two voyages is ...

... (d+43) + d = 1003

... 2d = 960 . . . . . . . subtract 43

... d = 480 . . . . . . . . divide by 2

The second voyage lasted 480 days.

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3 years ago

Two drivers, Alison and Kevin, are participating in a drag race. Beginning from a standing start, they each proceed with a const

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Answer:

Alison wins against Kevin by 0.93 s

Step-by-step explanation:

Alison covers the last 1/4 of the distance in 3 seconds, at a constant acceleration $a_a$ , we have the following equation of motion

$s/4 = a_at_a^2/2$

where s (m) is the total distance, ta = 3 s is the time

$s = 4a_a3^2/2 = 18a_a$

$a_a = s/18$

Similarly, Kevin overs the last 1/3 of the distance in 4 seconds, at a constant acceleration $a_k$ , we have the following equation of motion:

$s/3 = a_kt_k^2/2$

tk = 4 s is the time

$s = 3a_k4^2/2 = 24a_k$

$a_k = s/24$

Since $a_a = s/18$ we can conclude that $a_a > a_k$ , so Alison would win.

The time it takes for Alison to cover the entire track

$s = a_aT_a^2/2$

$T_a^2 = 2s/a_a = 2s/(s/18) = 36$

$T_a = \sqrt{36} = 6 s$

The time it takes for Kevin to cover the entire track

$s = a_kT_k^2/2$

$T_k^2 = 2s/a_k = 2s/(s/24) = 48$

$T_a = \sqrt{48} = 6.93 s$

So Alison wins against Kevin by 6.93 - 6 = 0.93 s

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3 years ago

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I hope this Helps!

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