Ask question

Ask question

All categories

elena-14-01-66 [18.8K]

2 years ago

7

I'll give the BRAINLIEST Basically everything is in the picture PLEASE HELP me ASAP IM BEGGING

1 answer:

Mariana [72]2 years ago

4 0

Answer: 110.71cm^2

Step-by-step explanation:Area of the shaded region is area if the whole rectangle subtracted from area of the semicircle (of diameter 9cm)

You might be interested in

How would you write 6 × 6 × 6 × 6 as an exponential expression?

stepan [7]

The answer is 6⁴.

Exponent is the number of times the factor is being multiplied. For example:
x * x = x²
x * x * x = x³
x * x * x * x = x⁴
....
So:
6 * 6 * 6 *6 = 6⁴

8 0

3 years ago

I WILL GIVE BRAINLY!! HELP!! ASAP!! Links WILL be reported... thank you.

marissa [1.9K]

Answer:

my answer would be c. y=lX+7l

3 0

2 years ago

Jordan and Ellen recycle cans. Jordan recycles 7 cans for every 12 cans Ellen recycles. Last week, Jordan recycles 42 cans.

ruslelena [56]

Answer:

are there multiple choices?

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

PLS HELP<br> If f(x) = x2 -1, what is the equation for f–1(x)?

Anon25 [30]

We have a function,

$f(x)=x^2-1$

and we are asked to find its inverse function.

An inverse function essentially gets you the original value that was dropped into a function.

For example,

If I put 5 into $f(x)$ I will get 24. Now If I take 24 and put it into the inverse function I have to get number 5 back.

The way to determine the inverse function swap the x and the $f(x)$ , then solve for $f(x)$ ,

$x=f(x)^2-1$

$f(x)^2=x+1$

$f(x)=\pm\sqrt{x+1}$

Of course the notation demands that the obtained function be called,

$f^{-1}(x)=\pm\sqrt{x+1}$

Hope this helps :)

6 0

2 years ago

What is the equation of the circle with center (5,-4) and containing the points (5,-2)

gtnhenbr [62]

Answer:

The equation of a circle is $(x-5)^2+(y+4)^2=4$ .

Step-by-step explanation:

-The equation of a circle is:

$(x-h)^2+(y-k)^2=r^2$ (where center is $(h,k)$ , the point $(x_{1},y_{1})$ and the radius known as $r$ ).

-Use the center (5,-4) and the point (5,-2) for the equation:

$(5-5)^2+(-2+4)^2=r^2$

-Solve the equation:

$(5-5)^2+(-2+4)^2=r^2$

$0 + (-2)^2=r^2$

$4 = r^2$

$\sqrt{4} = \sqrt{r^2}$

$2 = r$

-After you found the radius, use the center (5, -4) and radius 2 to get the equation of a circle:

$(x-5)^2+(y+4)^2=2^2$

-Then, after you have the equation, the radius needs to simplified by the exponent:

$(x-5)^2+(y+4)^2=4$

3 0

2 years ago