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spayn [35]
3 years ago
7

You are standing amongst a crowd for a parade that is 10 feet deep, on both sides of the street, and 1 mile long. If each person

occupies 2 square feet, estimate the number of people watching the parade.
52,800 people
26,400 people
13,200 people
200 people
Mathematics
2 answers:
NISA [10]3 years ago
8 0

Answer:

The number of people watching the parade is 26,400

Step-by-step explanation:

Breadth of crowd = 10 feet

Length of crowd = 1 mile = 5280 feet

Area of crowd = Length \times Breadth

                       = 5280 \times 10  

                       = 52800ft^2  

1 person occupy space = 2 sq.feet

No. of persons occupy 52800ft^2  space :

= \frac{52800}{2}

= 26400  

Hence the number of people watching the parade is 26,400

ollegr [7]3 years ago
5 0

We know that on each side of the street it is 10 feet deep and 1 mile long, which 1 mile = 5280 feet. So, lets get the area first.

First get the area of one side of the street. Note *  means to multiply

10ft * 5280ft = 52800\ ft^2

We know that one person occupies 2 square feet so

1 person = 2\ ft^2

We take 52800 and divide it by 2, which 2 represent 1 person

26400 / 2 = 26400

Now we know that one side represent 26400 people. We have two sides so we times this by 2


26400 * 2 = 52800 people

Answer = 52,800

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Solve the inequality for x. Show each step of the solution.10x &gt; 2(8x – 3) – 18
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Answer: x<4

Given the inequality:

10x>2(8x-3)-18

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First, distribute the bracket on the right side of the inequality.

\begin{gathered} 10x>2(8x)-2(3)-18 \\ 10x>16x-6-18 \\ 10x>16x-24 \end{gathered}

Next, subtract 10x from both sides of the inequality.

\begin{gathered} 10x-10x>16x-10x-24 \\ 0>6x-24 \end{gathered}

Add 24 to both sides of the inequality.

\begin{gathered} 0+24>6x-24+24 \\ 24>6x \end{gathered}

Divide both sides of the inequality by 6.

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6 0
1 year ago
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solong [7]
Could you retake the picture it’s hard to read
3 0
3 years ago
each of the 20 balls is tossed independently and at random into one of the 5 bins. let p be the probability that some bin ends u
amm1812

if p is the probability that some bin ends up with 3 balls and q is the probability that every bin ends up with 4 balls. pq is 16.

First, let us label the bins with 1,2,3,4,5.

Applying multinomial distribution with parameters  n=20  and  p1=p2=p3=p4=p5=15  we find that probability that bin1 ends up with 3, bin2 with 5 and bin3, bin4 and bin5 with 4 balls equals:

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But of course, there are more possibilities for the same division  (3,5,4,4,4)  and to get the probability that one of the bins contains 3, another 5, et cetera we must multiply with the number of quintuples that has one 3, one 5, and three 4's. This leads to the following:

p=20×5−2020!3!5!4!4!4!

In a similar way we find:

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So:

pq=20×4!4!4!4!4!3!5!4!4!4!=20×45=16

thus, pq = 16.

To learn more about Probability visit: brainly.com/question/29508225

#SPJ4

7 0
1 year ago
What is the value of x? ​
Alexandra [31]

Answer:

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Step-by-step explanation:

8 0
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