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spayn [35]
3 years ago
7

You are standing amongst a crowd for a parade that is 10 feet deep, on both sides of the street, and 1 mile long. If each person

occupies 2 square feet, estimate the number of people watching the parade.
52,800 people
26,400 people
13,200 people
200 people
Mathematics
2 answers:
NISA [10]3 years ago
8 0

Answer:

The number of people watching the parade is 26,400

Step-by-step explanation:

Breadth of crowd = 10 feet

Length of crowd = 1 mile = 5280 feet

Area of crowd = Length \times Breadth

                       = 5280 \times 10  

                       = 52800ft^2  

1 person occupy space = 2 sq.feet

No. of persons occupy 52800ft^2  space :

= \frac{52800}{2}

= 26400  

Hence the number of people watching the parade is 26,400

ollegr [7]3 years ago
5 0

We know that on each side of the street it is 10 feet deep and 1 mile long, which 1 mile = 5280 feet. So, lets get the area first.

First get the area of one side of the street. Note *  means to multiply

10ft * 5280ft = 52800\ ft^2

We know that one person occupies 2 square feet so

1 person = 2\ ft^2

We take 52800 and divide it by 2, which 2 represent 1 person

26400 / 2 = 26400

Now we know that one side represent 26400 people. We have two sides so we times this by 2


26400 * 2 = 52800 people

Answer = 52,800

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Ramesh marks 48,56,98 what is average
gizmo_the_mogwai [7]

Answer:

Ramesh scores about 67.3

Step-by-step explanation:

To find average we need add all the numbers and divide by the number of numbers so:

48+56+98=202

202/3= 67.333

67.33%

4 0
3 years ago
The product of two consecutive even integers is 360360. find the integers.
professor190 [17]
There are no 2 consecutive integers which give a product 360360
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X+y=1 If x=0, then y=
Ber [7]

Answer:

1

Step-by-step explanation:

x+y=1 if x=0, then y=1

5 0
2 years ago
What is the answer to this problem?<br> (15)18+89*56/7= ?
Fiesta28 [93]

Hello there, the answer to your question is:

982



8 0
3 years ago
Read 2 more answers
What are the x and y intercepts of f(x) = x2-x-12/x2+5x+6 and is there a hole? ​
stiv31 [10]

Answer:

There are no holes. The VAs are x=4 & x=-4  the HA is  x=2 the x intercepts are  (-3,0) & (3,0)  and the y intercept is (0,9/8).

Step-by-step explanation:

Given  f ( x ) =2 x ^2 − 18/x^2-16

find all asymptotes, holes and intercepts.

Factor the numerator and denominator.

f ( x ) =2 ( x ^2 − 9 )/( x + 4 ) ( x − 4 )

f ( x ) =2 ( x +3 ) ( x − 3 )/( x + 4 ) ( x − 4 )

A hole exists when the numerator and denominator contain the same factor (a factor "cancels out"). This function has no holes.

To find the vertical asymptote(s) (VA), find the values of  x

which make the denominator equal zero. The function is undefined at these values of  x

because you cannot divide by zero.

Set each factor of the denominator equal to zero and solve.

x + 4 = 0  and x − 4 = 0

x = − 4  and  x = 4

These are the VAs.

To find the horizontal asymptote(HA), compare the degree of the numerator and denominator. If the degrees are the same, the HA is the ratio of the leading coefficients.

For  f ( x) =2 x ^2 − 18/x^2-16

the degree in both numerator and denominator is  2

and the ratio of the leading coefficients is 2/1=1

The HA is  x = 2

The  x  intercept is the value at which the function (or "y") equals zero. If the numerator is zero, the function equals zero.

2 ( x + 3 ) ( x − 3 ) = 0

x + 3 = 0    x − 3 = 0

x = − 3   and  x = − 3

The  x  intercepts are  ( − 3 , 0 )  and  ( 3 , 0 ) .

The  y  intercepts are found by setting  x = 0 .

f ( 0 ) = 2 ( 0 ) ^2 − 18/( 0 )^2 − 16 = 9 /8

The  y  intercept is  ( 0 , 9/ 8 ) .

graph{(2x^2-18)/(x^2-16) [-10.04, 9.96, -3.56, 6.44]}

HOPE THIS HELPS YOU!!!!

        =)

4 0
3 years ago
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