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2 years ago

7

PLZ HELP ASAP ASAP ASAP!!!!!!!VPLZ HELP ASAP ASAP ASAP!!!!!!!VPLZ HELP ASAP ASAP ASAP!!!!!!!PLZ HELP ASAP ASAP ASAP!!!!!!!PLZ HE

LP ASAP ASAP ASAP!!!!!!!PLZ HELP ASAP ASAP ASAP!!!!!!!PLZ HELP ASAP ASAP ASAP!!!!!!!PLZ HELP ASAP ASAP ASAP!!!!!!!

2 answers:

Step2247 [10]2 years ago

8 0

Answer:

its 56 or 45

Step-by-step explanation:

56

Arlecino [84]2 years ago

7 0

Answer:

y=x*7

Step-by-step explanation:

63=9*7

28=4*7

14=2*7

77=11*7

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Draw a model and write an equation to represent 4 times as many as 3 is 12 explain your work

trasher [3.6K]

4x3=12. Think of it like this... 4 times as many as 3 is 12 (x)
(=)

So 4 times is 4 multiplied by....... 3 is just 3.... is means equals.... and the answer is 12. Your welcome, I hope I helped.

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2 years ago

Read 2 more answers

The variable Z is directly proportional to X. When X is 12, Z has the value 228. What is the value of Z when X = 18

Gnoma [55]

Z=Xk228=12kk=228/12k=19Z=18*19Z=342 57=3k57/3=k19=k again Z=8*19Z=152
hope i could help :)

6 0

2 years ago

1-tanA÷1+tanA=1-sin2A÷cos2A

Aleksandr-060686 [28]

hope u get it. I've used RHS to prove LHS

7 0

2 years ago

Please give the actual answer if you choose to anwser

zlopas [31]

9514 1404 393

Answer:

C. 78°

Step-by-step explanation:

The sum of angles in a triangle is 180°.

(7x-6)° +(4x+11)° +43° = 180°

11x +48 = 180 . . . . . divide by °, simplify

11x = 132 . . . . . . . subtract 48

x = 12 . . . . . . . divide by 11

Then the measure of angle T is ...

∠T = (7x -6)° = (7(12) -6)°

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6 0

3 years ago

1. Find the Least Common Multiple of these two monomials:<br> See picture

gtnhenbr [62]

Answer:

<em>The last choice is correct</em>

<em /> $LCM=120a^4b^7c^5$ <em />

Step-by-step explanation:

<u>Least Common Multiple (LCM)</u>

To find the LCM we can follow this procedure:

List the prime factors of each monomial.

Multiply each factor the greatest number of times it occurs in either factor.

We have two monomials:

$12a^4b^2c^5$

$40a^3b^7c^1$

The prime factors of the first monomial are:

$2^2,3,a^4,b^2,c^5$

The prime factors of the second monomial are:

$2^3,5,a^3b^7c^1$

LCM = Multiply $2^3*3*5*a^4*b^7*c^5$

These are all the factors the greatest number of times they occur.

Operating:

$LCM=8*15*a^4*b^7*c^5$

$\boxed{LCM=120a^4b^7c^5}$

The last choice is correct

3 0

3 years ago