Find the points of intersection of the circles.
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Answer:
Step-by-step explanation:
You need to solve the area sector of the bigger circle. Since we now the length of sector is 270, we can set up an equation.
Length of sector DC = 2r
270 = 2(8+OA) *(8+OA is the raidus of the bigger circle/sector)*
270/2 = 8 + OA (division)
135/ -8 = OA
135/ -8 = OB (because OA and OB are the raidus of the same circle, so they are congruent)
I hope this helps you! Please correct me if you see a miscalculation <3<3
y = mx + b
"m" is the slope, "b" is the y-intercept (the y value when x = 0)
To find the slope, you can use the slope formula and plug in the two points:
(3,63) = (x₁ , y₁)
(5,107) = (x₂, y₂)
m = 22
Now that you know m = 22, plug it into the equation:
y = mx + b
y = 22x + b
To find "b", plug in one of the points into the equation (I will do both points)
(3,63)
y = 22x + b
63 = 22(3) + b
63 = 66 + b Subtract 66 on both sides
-3 = b
(5,107)
y = 22x + b
107 = 22(5) + b
107 = 110 + b Subtract 110 on both sides
-3 = b
y = 22x - 3