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svp [43]
3 years ago
15

James determined that these two expressions were equivalent expressions using the values of x = 4 and x = 6. Which statements ar

e true? Check all that apply
Mathematics
2 answers:
GarryVolchara [31]3 years ago
6 0

Answer:

When x=2, both expressions have a value of 18.

The expressions have equivalent values for any value of x.

The expressions have equivalent values if x=8

Step-by-step explanation:

James determined that these two expressions were equivalent expressions using the values of x = 4 and x = 6. Which statements are true? Check all that apply. 7 x + 4 and 3 x + 5 + 4 x minus 1

When x = 2, both expressions have a value of 18.

7x + 4

= 7(2) + 4

= 14 + 4

= 18

3x + 5 + 4x - 1

3(2) + 5 + 4(2) - 1

6 + 5 + 8 - 1

= 18

The expressions are only equivalent for x = 4 and x = 6.

• This is not true because the expression is also equivalent for x = 2

The expressions are only equivalent when evaluated with even values.

When x = 1

7x + 4

7(1) + 4

= 7 + 4

= 11

3x + 5 + 4x - 1

3(1) + 5 + 4(1) - 1

3 + 5 + 4 - 1

= 11

The expressions have equivalent values for any value of x.

Yes, it has an equivalent value at any value of x

The expressions should have been evaluated with one odd value and one even value.

When x = 0, the first expression has a value of 4 and the second expression has a value of 5.

7x + 4

7(0) + 4

= 0 + 4

= 4

3x + 5 + 4x - 1

3(0) + 5 + 4(0) - 1

0 + 5 + 0 -1

= 4

The expressions have equivalent values if x = 8.

7x + 4

7(8) + 4

56 + 4

= 60

3x + 5 + 4x - 1

3(8) + 5 + 4(8) - 1

24 + 5 + 32 - 1

= 60

Sladkaya [172]3 years ago
4 0

Answer:

1,4,7

Step-by-step explanation:

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The circumference of a sphere was measured to be 82 cm with a possible error of 0.5 cm.
Nat2105 [25]

Answer:

A) Maximum error = 170.32 cm³

B)Relative error = 0.0575

Step-by-step explanation:

A) Formula for circumference is: C = 2πr

Differentiating with respect to r, we have;

dC/dr = 2π

r is small, so we can write;

ΔC/Δr = 2π

So, Δr = ΔC/2π

We are told that ΔC = 0.5.

Thus; Δr = 0.5/2π = 0.25/π

Now, formula for Volume of a sphere is;

V(r) = (4/3)πr³

Differentiating with respect to r, we have;

dV/dr = 4πr²

Again, r is small, so we can write;

ΔS/Δr = 4πr²

ΔV = 4πr² × Δr

Rewriting, we have;

ΔV = ((2πr)²/π) × Δr

Since C = 2πr, we now have;

ΔV = (C²/π)Δr

ΔV will be maximum when Δr is maximum

Thus, ΔV = (C²/π) × 0.25/π

C = 82 cm

Thus;

ΔV = (82²/π) × 0.25/π

ΔV = 170.32 cm³

B) Formula for relative error = ΔV/V

Relative error = 170.32/((4/3)πr³)

Relative error = 170.32/((4/3)C³/8π³)

Relative errror = 170.32/((4/3)82³/8π³)

Relative error = 170.32/2963.744

Relative error = 0.0575

3 0
3 years ago
Lydia received her salary on Friday. She spent one-half of her salary on rent and then spent $168 on her electric and water bill
inysia [295]

Answer:

B. $466

How:

You would have to add up all KNOWN expense that Lydia made and then the money the she spent on rent would be an exact replica of that.

7 0
3 years ago
London bought a bag containing 95 small candies. She starts eating the
Savatey [412]

Answer: 19

Step-by-step explanation: let the number of candies left in the bag be y and the number of minutes eating be x.

Because she eats 5  candies per minute

8 0
2 years ago
A fraction in which the GCF of the numerator and the denominator is 1 is written in
konstantin123 [22]
"lowest terms". Whenever 2 numbers have a GCF of 1, that means there isn't anything that can divide out of both numbers, which is called "lowest terms." It means that the fraction cannot be reduced any more.
5 0
3 years ago
A rectangular swimming pool has a base of 200 square feet. The pool has a depth of 5 feet.
Goshia [24]

Answer:

D.) 1,000 ft³



If the base of the pool is 200 square feet in size, then we can just multiply 200 by the depth of 5 to equal 1,000 ft³ which is equal to the volume of the pool.












Step-by-step explanation:

Have a great rest of your day
#TheWizzer

6 0
2 years ago
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