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Ronch [10]
3 years ago
5

How do you subtract 3/4-3/8 using simplest form

Mathematics
1 answer:
lbvjy [14]3 years ago
8 0

Answer:

Hello there, I love answering these questions!

Step-by-step explanation: turn 3/4 into 6/8 = 3x2/4x2 then subtract. 6/8 - 3/8 = 3/8

Hope this helped you! Have a wonderful day!


You might be interested in
Y = 5x - 13<br><br> 4x + 3y = 18
hram777 [196]
<span>replace Y = 5x - 13
into
4x + 3y = 18

</span>

4x + 3 (5x - 13) = 18
4x + 15 - 39 = 18
4x -24 = 18
4x = 18 +24
4x = 42
x = 42/4
x = 10.5

Y = 5(10.5) - 13
=  52.5 - 13
= 39.5

answer: x = 10.5 and y = 39.5
3 0
3 years ago
. Find the value of $1,300 invested at 4.2% interest compounded continuously for 5 years, 9 months. Round your final answer to t
BARSIC [14]
The formula we use for continuous compounding is A=Pe ^{rt} where P is the initial amount invested, r is the rate as a decimal, and t is time in years.  Our P = 1300, our r = .042, and our t = 5.75 (9 months is 3/4 of a year, and 3/4 in a decimal is .75).  Putting all that into our formula we have A=1300(2.718) ^{(.042)(5.75)}.  We have to multiply those 2 powers together and then raise euler's number to it, then multiply by 1300.  Doing all of that, we get the amount at the end to be $1,655.10
5 0
3 years ago
Five cards are drawn from a standard 52-card playing deck. A gambler has been dealt five cards—two aces, one king, one 3, and on
Nookie1986 [14]

Answer:

The probability that he ends up with a full house is 0.0083.

Step-by-step explanation:

We are given that a gambler has been dealt five cards—two aces, one king, one 3, and one 6. He discards the 3 and the 6 and is dealt two more cards.

We have to find the probability that he ends up with a full house (3 cards of one kind, 2 cards of another kind).

We know that gambler will end up with a full house in two different ways (knowing that he has given two more cards);

  • If he is given with two kings.
  • If he is given one king and one ace.

Only in these two situations, he will end up with a full house.

Now, there are three kings and two aces left which means at the time of drawing cards from the deck, the available cards will be 47.

So, the ways in which we can draw two kings from available three kings is given by =  \frac{^{3}C_2 }{^{47}C_2}   {∵ one king is already there}

              =  \frac{3!}{2! \times 1!}\times \frac{2! \times 45!}{47!}           {∵ ^{n}C_r = \frac{n!}{r! \times (n-r)!} }

              =  \frac{3}{1081}  =  0.0028

Similarly, the ways in which one king and one ace can be drawn from available 3 kings and 2 aces is given by =  \frac{^{3}C_1 \times ^{2}C_1 }{^{47}C_2}

                                                                   =  \frac{3!}{1! \times 2!}\times \frac{2!}{1! \times 1!} \times \frac{2! \times 45!}{47!}

                                                                   =  \frac{6}{1081}  =  0.0055

Now, probability that he ends up with a full house = \frac{3}{1081} + \frac{6}{1081}

                                                                                    =  \frac{9}{1081} = <u>0.0083</u>.

3 0
3 years ago
Read 2 more answers
Grade 7 math extra credit
Nonamiya [84]
2400 in prize money...

the first winner will receive 1/3 of the money..
1/3 * 2400 = 2400/3 = 800
leaving 2400 - 800 = 1600

the next 10 winners will receive 1/10 of the remaining amount
1/10 * 1600 = 1600/10 = 160 <== each will receive $ 160
3 0
3 years ago
In choosing this year 327 voted musical and 115 voted drama. How many more students voted musical than drama
Lapatulllka [165]

Answer:

212 more student voted musical than drama .

Step-by-step explanation:

As given

In choosing this year 327 voted musical and 115 voted drama.

More students voted musical than drama = Total students voted for musical - Students voted for drama .

Putting values in the above

More students voted musical than drama = 327- 115

                                                                      = 212

Therefore 212 more student voted musical than drama .

5 0
3 years ago
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