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Anestetic [448]
3 years ago
8

luna had $50 when she got to the carival after riding 12 rides she had $26 dollars left what was the price of each ride

Mathematics
1 answer:
Orlov [11]3 years ago
4 0
It's $4.17 I believe
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Find the median of the data
kicyunya [14]
The median is the middle number of the data plot. Since there 30 numbers, there isn't a exact middle. To find the median you must add the two middle number then divide by 2. 
In this case you must add 87 and 88 which gives 175.
Then divide 175 by 2 which gives 87.5
87.5 is the median
5 0
2 years ago
<img src="https://tex.z-dn.net/?f=y%3Dx%5E%7B2%7D%20%2B3" id="TexFormula1" title="y=x^{2} +3" alt="y=x^{2} +3" align="absmiddle"
Katena32 [7]

Answer:

The domain is (negative infinity, infinity) the range is [3. Infinity) y>=3

Step-by-step explanation:

The domain for all quadratic functions are (Negative infinity, infinity)

The range is the output values of the function 3, to infinity

6 0
3 years ago
How do you solve this?
Alchen [17]
The answer is (3x^2 - x +2 )= to AC
Area = 1/2 |BD| |AC|
(9x^3 - 3x^2 + 6x) = 1/2 (AC) 6x
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3 0
3 years ago
Please help! I dont understand this!
deff fn [24]
75 is equivalent to 0.75 and

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3 0
3 years ago
two positive numbers x and y, with the maximum value 4, add up to 5. what is the difference between the maximum and minimum valu
Svetach [21]

Answer:

  92

Step-by-step explanation:

Since the sum of the two numbers is 5, we can represent one of them by x and the other by 5-x. Then the desired product is ...

  x²(5-x)³

A graphing calculator can show the extreme values of this on the interval 1 ≤ x ≤ 4. The maximum is 108 at x=2; the minimum is 16 at x=4.

The difference between the maximum and minimum is 108-16 = 92.

_____

If you like, you can take the derivative and set it to zero.

  f(x) = x²(5 -x)³

  f'(x) = 2x(5 -x)³ +x²(-3)(5-x)² = x(5 -x)²(2(5-x) -3x)

  f'(x) = 5x(5-x)²(2-x)

This will be zero for x=0, x=5, and x=2. The points at x=0 and x=5 represent minima in the product. The values x=0 and x=5 are not in the domain of interest. The point at x=2 represents a maximum.

To find the function extremes on an interval, we need to evaluate the function where the derivative is zero, and also at the ends of the interval. So, the function values of interest are ...

  f(1) = 1²·4³ = 64

  f(2) = 2²·3³ = 108 . . . . product maximum

  f(4) = 4²·1³ = 16 . . . . . . product minimum

The difference between the maximum and minimum is 92.

5 0
3 years ago
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