Using synthetic division, Find k so that when x³+2kx² +3x-6 is divided by x+3 the remainder is 12.

Sue withdrew $85 a month from her savings account for 7 months. what was the change in her balance?

Ivan

Answer:

-595 was the change in her balance

Step-by-step explanation:

85*7=595

Withdrew=Negative(-)

8 0

4 years ago

3) the product of x and y is less than or equal to 4

jekas [21]

Answer:

x×y=<4

Step-by-step explanation:

let x and y d equal to 2

2×2=4

let x x is one and y is 3

1×3=3

3 0

3 years ago

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What is 15.8 in expanded form And What is 1.058 in expanded form and last what is 0.158 in expanded form

xeze [42]

1) 10.0 + 5.0 + .8
2) 1.000 + 0.050 + 0.008
3) 0.000 + 0.100 + 0.050 + 0.008

5 0

4 years ago

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Find the measure of missing angles. A= B= C=

vlada-n [284]

Answer:

A = 140°

B = 40°

C = 140°

Step-by-step explanation:

1. Since we know that opposite angles are equal, b = 40°

2. Since we also know that the angle of a line adds to 180°,

a = 180° - 40°

So, 140°

Then repeat step 1 to find C through A.

3 0

3 years ago

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Using the frequency table given, find the mean, median, and mode.

aalyn [17]

Answer:

$Mean = 69$

$Mode = 66$

$Median = 69$

Step-by-step explanation:

Given

The frequency table

Required

Determine the mean, median and mode

Calculating Mean

$Mean = \frac{\sum fx}{\sum f}$

Where

fx = product of frequency and inches

f = frequency

So;

$Mean = \frac{63 * 2 + 65 * 1 + 66 * 4 + 67 * 3 + 68 * 1 + 69 * 2 + 70 * 2 + 71 * 1 + 72 * 3 + 74 * 2 + 75 * 2}{2 + 1 + 4 + 3 + 1 + 2 + 2 + 1 + 3 + 2 + 2}$

$Mean = \frac{1587}{23}$

$Mean = 69$

Calculating Mode

$Mode = 66$

Because it highest frequency of 4

Calculating Median

$Median = \frac{\sum f}{2}th\ position$

$Median = \frac{2 + 1 + 4 + 3 + 1 + 2 + 2 + 1 + 3 + 2 + 2}{2}th\ position$

$Median = \frac{23}{2}th\ position$

$Median = 11.5th\ position$

Approximate

$Median = 12th\ position$

At this point we, need to get the cumulative frequency (CF)

Inches ---- Frequency ---- CF

63 -------------2------------------2

65 -------------1------------------3

66 -------------4------------------7

67 -------------3------------------10

68 -------------1------------------11

69 -------------2------------------13

70 -------------2------------------15

71 -------------1------------------16

72 -------------3------------------19

74 -------------2------------------21

75 -------------2------------------23

From the above table

Since the median fall in the 12th position, then we consider the following data

69 -------------2------------------13

because it has a CF greater than 12

Hence;

$Median = 69$

7 0

4 years ago