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Roman55 [17]
2 years ago
8

Y = -7(-13) 1.-91 2.21 3.91 4.-21

Mathematics
1 answer:
victus00 [196]2 years ago
4 0
The answer is 3 so 91
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-9.b = 45<br> b =<br> What is the answer I need to know the answe
BaLLatris [955]

Answer:

b=-5

Step-by-step explanation:

Divide by -9 to eliminate the -9 on -9b

(Since -9b is the same thing as -9 times b we can use the inverse of multiplication which is division to eliminate the -9 from b but we need to do it on both sides to make it balance)

-9b/-9=45/-9

b=-5

7 0
2 years ago
Given A = {x ∈ ℤ : 4|x} and B = {x ∈ ℤ : 2|x}. Prove A ⊆ B.
Rashid [163]

Let a ∈ A. Then a is some integer that is divisible by 4, so we can write a = 4k for some integer k.

We can simultaneously rewrite a as a = 2•2k, so 2 clearly divides a, which means a ∈ B as well.

Therefore A ⊆ B.

4 0
2 years ago
What value of x is in the solution set of 8x – 6 &gt; 12 + 2x?
Crazy boy [7]

Answer:

ur answer is there !!!

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8 0
3 years ago
Read 2 more answers
An object is placed 21 cm from a concave lens of focal length 25 cm. what is the magnification?
wariber [46]

The magnification is 0.54

Given,

The distance between object and concave lens, u = -21 cm

Focal length of the concave lens, f = -25 cm

Let m be the magnification.

m = v/u

Here v is the position of image.

We have to find v first.

By using lens equation we can determine v.

That is,

1/f = 1/v – 1/u

So,

- (1/25) = 1/v – (-1/21)

- (1/25) = 1/v + 1/21

1/v = - (1/25) – 1/21

1/v = (-25 – 21) / (21 x 25)

1/v = - (46/525)

Therefore v = - (525/46)

   v = -11.41 cm

Now we have to find magnification, m.

m = v/u

   = (-11.41) / (-21)

   = 0.54

Here magnification is 0.54

Learn more about concave lens here: brainly.com/question/12944945

#SPJ4

6 0
2 years ago
Your lab develops a synthetic compound that is extremely light but very durable. You test it by making a solid ball with a radiu
Maksim231197 [3]
The volume of a spherical shaped object is given by

V= \frac{4}{3} \pi r^3

Given that the <span>solid ball has a radius of 20.0 millimeters, the volume of the solid ball is given by

V= \frac{4}{3} \pi(20)^3\approx33,510mm^3

Therefore, the </span><span>closest to the volume of the synthetic compound ball, in cubic millimeters is 33,500 cubic milimeters.</span>
6 0
3 years ago
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