Given the coordinates of the image of line segment RT to be R'(-2,-4) and T'(4.4), if the image produced was dilated by a scale factor of 12 centered at the origin, to get the coordinate of the end point, we will simply multiply the x and y coordinates of by the factor of 12 as shown:
For R' with coordinate R'(-2,-4), the coordinates of endpoint of the pre-image will be:
R = 12R'
R = 12(-2, -4)
R = (-24, -48)
For T' with coordinate T'(4,4), the coordinates of endpoint of the pre-imagee will be:
T = 12T'
T = 12(4, 4)
T = (48, 48)
Hence the coordinate of the endpoint of the preimage will be at R(-24, -48) and T(48, 48)
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Answer:
(x, y) = (-8.625, -63)
Step-by-step explanation:
Substitute for y.
-63 = 8x +6
-69 = 8x . . . . . subtract 6
-69/8 = x = -8.625
The solution is (x, y) = (-8.625, -63).
Answer:
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Step-by-step explanation:
