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Savatey [412]
4 years ago
6

If one triangle is JKL and the other one is UVW what angle is congryent to the angle L

Mathematics
1 answer:
klio [65]4 years ago
3 0

Answer:

angle L is congruent to angle W

Step-by-step explanation:

Corresponding parts of similar triangles are congruent/similar. It is for angles therefore the W and L are equal

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Write an ordered pair for each point graphed below.
Viefleur [7K]

Answer:

\boxed{(-1,4)}

Step-by-step explanation:

The point is located in Quadrant II of the graph, where x-values are negative and y-values are positive.

Each marking on the graph represents one unit of distance. The two <em>axes</em> meet at the origin, where the coordinate point is equal to (0,0).

So, you can count backwards once from the origin to get your x-value ⇒ -1 and count up upwards four times from x=-1 to get your y-value ⇒ 4.

Finally, place these in a coordinate point (x,y) ⇒ \boxed{(-1,4)}.

5 0
3 years ago
Read 2 more answers
Find the domain and range of each function. 1.g(x)=x^3
qaws [65]

Domain: (-∞,∞) or All real numbers

Range: (-∞,∞) or All real numbers

6 0
3 years ago
3) -x + 5 = -11x + 25
konstantin123 [22]

Answer:

x=2

Step-by-step explanation:

-x+5=-11x+25

add +x on both sides -11x+x =-10x

-10x+25=5

subtract 25 on both sides

you get -10x=-20

x=2

6 0
3 years ago
A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken
mihalych1998 [28]

Answer:

n=6147

Step-by-step explanation:

1) Notation and definitions

X=1 number of citrus trees that are infected with the citrus red mite.

n=5 random sample taken

\hat p=\frac{1}{5}=0.2 estimated proportion of citrus trees that are infected with the citrus red mite.

p true population proportion of citrus trees that are infected with the citrus red mite.

Me=0.01 represent the margin of error desired

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical values we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical values would be given by:

t_{\alpha/2}=-1.96, t_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.2(1-0.2)}{(\frac{0.01}{1.96})^2}=6146.56  

And rounded up we have that n=6147

5 0
4 years ago
Suppose you obtain a $1,300 T-note with a 9% annual rate, paid monthly, with maturity in 6 years. How much interest will be paid
Tems11 [23]
We know that,
Interest, I = \frac{P×R×T}{100}
Where, P = Principal = $1300
R = rate of interest = 9% annually = \frac{9}{12}%
T = Time  = 1 month

So, I = \frac{1300×[tex] \frac{9}{12}×1}{100} [/tex]
        = $9.75

Interest paid per month is $9.75
7 0
3 years ago
Read 2 more answers
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