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vodka [1.7K]
3 years ago
8

What is the measure of angle ABC ?

Mathematics
1 answer:
WARRIOR [948]3 years ago
6 0

Answer:

C

Step-by-step explanation:

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Please help,TYSM IF YOU HELP
FrozenT [24]

Answer:

rectangle irregular

Step-by-step explanation:

5 0
3 years ago
Solve the following equation: r2+6r=27
Feliz [49]
2r+6r=27

8r=27
*divide both side by 8
r=3.75
3 0
4 years ago
Read 2 more answers
Does the function below represent a linear function, an exponential function, a quadratic function, or none of these?
Butoxors [25]

The equation of the function given as (x)= 5 * 2^x is an exponential function

<h3>How to determine the function type?</h3>

The equation of the function is given as

f(x)= 5 * 2^x

An exponential function is represented as

f(x) = a * b^x

Where

Initial value = a

Rate = b

This means that

a = 5

b = 2

Hence, the equation of the function given as (x)= 5 * 2^x is an exponential function

Read more about exponential function at

brainly.com/question/27161222

#SPJ1

7 0
2 years ago
3-7*(16/2+3-1)+6 showing this work
lord [1]

Answer:-61

Step-by-step explanation:

3-7(16/2+3-1)+6

3-7(8+3-1)+6

3-7(10)+6

3-70+6

-67+6

-61

4 0
4 years ago
The difference of two numbers is 16 the greater number is five less than four times a small number find the two numbers
Elis [28]

Answer:

The numbers are 23 and 7  

Step-by-step explanation:

1. Set up the equations

   Let x = the greater number

  and y = the smaller number. Then

(1) x - y = 16

       4y = 4 times the smaller number and

  4y - 5 = 5 less than 4 times the smaller number. Then

(2)     x = 4y - 5

You have a system of two equations:

\begin{cases}(1) & x - y = 16\\(2) & x = 4y - 5\end{cases}

2. Solve the equations

\begin{array}{lrcll}(3) & 4y - 5 - y & = & 16 &\text{Substituted (2) into (1)}\\& 3y - 5 & = & 16 &\text{Simplified}\\ & 3y & = & 21 &\text{Added 5 to each side}\\(4) &y & = & \mathbf{7} &\text{Divided each side by 3} \\& x - 7 & = & 16 & \text{Substituted (4) into (1)}\\& x& = & \mathbf{23} & \text{Added 7 to each side}\\\end{array}

The larger number is 23; the smaller number is 7.

3. Check

\begin{array}{rclcrcl}23 - 7& = & 16 & \qquad &23&=&4(7) - 5\\16 & = & 16 & \qquad &23& = &28 - 5\\&&& \qquad &23& = &23\\\end{array}

OK.

3 0
3 years ago
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