Answer:
60
Step-by-step explanation:
Cot is the same as 1/tan so:
By rearranging the equation, we get:
By taking the inverse tan, we get:
Answer:
not statistically significant at ∝ = 0.05
Step-by-step explanation:
Sample size( n ) = 61
Average for student leader graduates to finish degree ( x') = 4.97 years
std = 1.23
Average for student body = 4.56 years
<u>Determine if the difference between the student leaders and the entire student population is statistically significant at alpha</u>
H0( null hypothesis ) : u = 4.56
Ha : u ≠ 4.56
using test statistic
test statistic ; t = ( x' - u ) / std√ n
= ( 4.97 - 4.56 ) / 1.23 √ 61
= 2.60
let ∝ = 0.05 , critical value = -2.60 + 2.60
Hence we wont fail to accept H0
This shows that the difference between the student leaders and the entire student population is not statistically significant at ∝ = 0.05
5*15.75=78.75
128-2=126
126-78.75=47.25
47.25/7=6.75
The length of each piece of the seven pieces would be 6.75 inches.
The number is 20. Work in picture if you want it or want justification of steps:)
I attached a picture of how I worked out the answer
