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Ganezh [65]
3 years ago
5

Given the function f(x), what is the transformation f(x)+r, if r is a real number and r > 0?

Mathematics
1 answer:
patriot [66]3 years ago
3 0

Answer:

C

Step-by-step explanation:

If r is a real number, then the x intercepts 0 < r, meaning r is greater than 0, you would shift right from 0 to your higher + number.

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Simplify the following expression. 4a^-2b<br><br> A.) b/4a^2<br> B.)4b/a^2<br> C.)1/4a^b2
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ANSWER

The correct answer is B

\frac{4b}{ {a}^{2} }


EXPLANATION

The given exponential expression is

4 {a}^{ - 2} b

We can rewrite this as,

4b \times  {a}^{ - 2}

We need to simplify to obtain a positive index, so we apply the following property,


{a}^{ - m}  =  \frac{1}{ {a}^{m} }

This implies that,


4b \times  {a}^{ - 2}  = 4b \times  \frac{1}{ {a}^{2} }

This will finally simplify to,

4b \times  {a}^{ - 2}  =\frac{4b}{ {a}^{2} }


Therefore the correct answer is B
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Step-by-step explanation:

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