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BARSIC [14]
3 years ago
10

Plz help plz plz plz plz

Mathematics
2 answers:
inysia [295]3 years ago
8 0
................................................

The answer is 15.
liq [111]3 years ago
8 0
I hope this helps you

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out of 300seniors at a local high school 40% went on a senior trip.at the hotel on room was reserved for every 4 students.how ma
Andreyy89
300 × .40=120
120/4=30 rooms
6 0
3 years ago
Please help me Urgent!!!!!
Tatiana [17]
Your answer are options: A, B D F
YOu can just say: 8x8=64
So, evrything biger or = 64, are the answer.
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a company produces 3 tons of cereal each week how many 12 ounces cereal boxes csn be filled in a week
SVEN [57.7K]
8000.hope this help if not tell me please.
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3 years ago
What is the difference between arcsin and sin^-1 ?
Len [333]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2094473

_______________


Both refer to the inverse sine function.

The inverse sine (or arcsine) of x:

\mathsf{f(x)=arcsin(x)=sin^{-1}(x)}


where x is a real number in the domain of the function:

\mathsf{-1\le x\le 1}


and the arcsine function returns an angle in the interval  \mathsf{\left[-\,\frac{\pi}{2},\,\frac{\pi}{2}\right]:}

\mathsf{-\,\dfrac{\pi}{2}\le arcsin(x)\le \dfrac{\pi}{2}}\quad\longleftarrow\quad\textsf{range of the inverse sine function.}


So if you see anywhere one of these expressions below

\mathsf{\theta=arcsin(x)~~or~~\theta=sin^{-1}(x)}


then you should look for an angle \theta that satisfies the following conditions:

\footnotesize\begin{array}{l}\bullet\end{array}\normalsize\begin{array}{l}\mathsf{sin\,\theta=x;} \end{array}\\\\\\
\footnotesize\begin{array}{l}\bullet\end{array}\normalsize\begin{array}{l}\mathsf{\dfrac{\pi}{2} \le \theta\le\dfrac{\pi}{2}.} \end{array}


This angle \theta is called the inverse sine of the real number x.

______


Pay attention and do not mistake the arcsine function for the reciprocal of sine (which is cosecant); especially if you prefer or see that notation with an superscript -1. This one can be easily mistaken for an exponent:

\mathsf{sin^{-1}(x)=arcsin(x)\qquad\quad\checkmark}


but the reciprocal is something like

\mathsf{\big[sin(x)\big]^{-1}=\dfrac{1}{sin\,(x)}=csc(x)\qquad\quad(!!)}

and this last one has a total different meaning.


I hope this helps. =)

6 0
4 years ago
If you can please help me with this question~ the question is the image :)
BaLLatris [955]

Answer:

B

Step-by-step explanation:

Start by using the distance formula to find the raidus

The two points are (-2,1) and (-4,1)

√((-4+2)²+(1-1)²)= 2

The radius is two and we have our center which means we can write

(x+2)²+(y-1)²=4

now it's just a matter of expanding everyhting

x²+4x+4+y²-2y-3=0

x²+y²+4x-2y+1=0

This is equal to B

4 0
3 years ago
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