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Rzqust [24]
3 years ago
13

Points and linr determine thr slope line (1,2) and (2,1)

Mathematics
1 answer:
kotegsom [21]3 years ago
4 0
Slope is (y2-y1)/(x2-x1)

(2-2)/(1-1)

slope is 0 which means it is a horizontal line.
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A month is randomly chosen. What is the probability that the month chosen has less than 31 days?
Rasek [7]

Well think about how many months there’s are!

12 right?

So 12 is the total of months or the denometor

Or bottom number ^^

Now how many months have 31 days?

Figure that out and that your numerator

5 0
2 years ago
Use the polynomial 3x^2−4x^11+4x^4−2x^10−5+^8x^8 to answer the question. 
Anit [1.1K]

Answer: 11

<u>Step-by-step explanation:</u>

3x² - 4x¹¹ + 4x⁴ - 2x¹⁰ - 5 + 8x⁸

To find the degree, look for the largest exponent.  <em>11</em>

If you put this polynomial in standard form (from largest to smallest exponent), the first term will give you the degree of the polynomial and the leading coefficient.

- 4x¹¹ - 2x¹⁰ + 8x⁸ + 4x⁴ + 3x² - 5

4 0
3 years ago
Read 2 more answers
Calculate X3 dx .<br><br>A.×2 + c<br>B. 3X2 + c<br>c . x4 + c<br>D . x4/4+c
olga nikolaevna [1]
\LARGE \int x^3 dx = \frac{x^4}{4}+C

So the answer is choice D. You can check this by differentiating the right hand side and you'll get x^3 back again. 

This answer can be found by using the power rule for integrals. That rule is

\LARGE \int x^n dx = \frac{x^{n+1}}{n+1} + C
4 0
3 years ago
What is the equivalent expression of 3p+12m+8
seropon [69]

Q.What is the equivalent expression of 3p+12m+8

A.12m+3p+8

Hope this helps:)

6 0
3 years ago
Read 2 more answers
Complete the table for the following function<br> y=(1/3)^x
Bumek [7]

x=-3 then y= 27

x= -2 then y= 9

x=2 then y: y=\frac{1}{9}

x=3 then y: y=\frac{1}{27}

The graph of the function decreases from left to right.

Option C is correct.

Step-by-step explanation:

We are given the function: y=(\frac{1}{3})^x

and we need to fill the table

if x = -3 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^-3

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^3 }\\y=\frac{1}{\frac{1}{27}}\\y=27

if x = -2 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^-2

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^2 }\\y=\frac{1}{\frac{1}{9}}\\y=9

if x = 2 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^2

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^2 }\\y=\frac{1}{9}

if x = 3 then y=?

Putting value of x in the given function:

y=(\frac{1}{3})^x

y=(\frac{1}{3})^3

Applying exponent rule a^-b= 1/a^b

y=\frac{1}{(\frac{1}{3})^3 }\\y=\frac{1}{27}

So, x=-3 then y= 27

x= -2 then y= 9

x=2 then y: y=\frac{1}{9}

x=3 then y: y=\frac{1}{27}

Graph of the function is shown in figure attached.

The graph of the function decreases from left to right.

Option C is correct.

Keywords: Solving Equations

Learn more about Solving Equations at:

  • brainly.com/question/1563227
  • brainly.com/question/2403985
  • brainly.com/question/11229113

#learnwithBrainly

7 0
3 years ago
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