Thanks in advance for the help
2 answers:
For this case we must find the graphical solution of the following system of equations:
In the attached image it is observed that the lines are parallel, they are intercepted in all the points. In addition, it is observed that if we divide the second equation by 5 we obtain:, if we now multiply by 3 we obtain:
. Being shown that the lines are equal, therefore, the system has more than one solution.
ANswer:
Option B
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Answer:
430 cm2
Step-by-step explanation:
The Lateral Surface Area of it is equal to:
Area of ABCD + Area of A'B'C'D' + Area of ABB'A' + Area of DCC'D' + Area of ADD'A' + Area of BCC'B'
As ABCDA'B'C'D' is a rectangle prism, so that:
+) Area of ABCD = Area of A'B'C'D'
+) Area of ABB'A' = Area of DCC'D'
+) Area of ADD'A' = Area of BCC'B'
=> Total lateral surface area = 2. Area ABCD + 2. Area ABB'A + 2. Area ADD'A
As ABCDA'B'C'D' is a rectangle prism, so that we have: ABCD, ABB'A', ADD'A' are rectangles.
The formula to calculate the area of rectangle is: Area = Length x Width
We have:
+) Area ABCD = AB x BC =11 x 10 = 110 cm2
+) Area ABB'A = AB x AA' = 11 x 5 = 55 cm2
+) Area ADD'A = AA' x A'D' = 5 x 10 = 50cm2
Total lateral surface area = 2. Area ABCD + 2. Area ABB'A + 2. Area ADD'A
= 2 x 110 + 2 x 55 + 2 x 50 = 430 cm2
