Question

G(x)=x^2+3x-3 What are the zeros of the function?

Answer 1

Answer:

(-3+$\sqrt{21}$) /2,  (3+$\sqrt{21}$) / 2 which is approx -3.791 and 0.791

Step-by-step explanation:

i used the quadratic formula:  [-b± sq rt (b² - 4ac) / 2a]

in this problem, a = 1, b = 3, and c = -3