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posledela
2 years ago
9

G(x)=x^2+3x-3 What are the zeros of the function?

Mathematics
1 answer:
krek1111 [17]2 years ago
6 0

Answer:

(-3+\sqrt{21}) /2,  (3+\sqrt{21}) / 2 which is approx -3.791 and 0.791

Step-by-step explanation:

i used the quadratic formula:  [-b± sq rt (b² - 4ac) / 2a]

in this problem, a = 1, b = 3, and c = -3

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