Answer:
Option A. 
Step-by-step explanation:
we know that
The area of the rectangle is equal to
A=LW
where
L is the length of rectangle
W is the width of rectangle
we have
Plot the vertices
see the attached figure
L=AD=BC
W=AB=DC
the formula to calculate the distance between two points is equal to
<em>Find the distance AD</em>
substitute in the formula
<em>Find the distance AB</em>
substitute in the formula
Find the area
Answer:
The objective function in terms of one number, x is
S(x) = 4x + (12/x)
The values of x and y that minimum the sum are √3 and 4√3 respectively.
Step-by-step explanation:
Two positive numbers, x and y
x × y = 12
xy = 12
S(x,y) = 4x + y
We plan to minimize the sum subject to the constraint (xy = 12)
We can make y the subject of formula in the constraint equation
y = (12/x)
Substituting into the objective function,
S(x,y) = 4x + y
S(x) = 4x + (12/x)
We can then find the minimum.
At minimum point, (dS/dx) = 0 and (d²S/dx²) > 0
(dS/dx) = 4 - (12/x²) = 0
4 - (12/x²) = 0
(12/x²) = 4
4x² = 12
x = √3
y = 12/√3 = 4√3
To just check if this point is truly a minimum
(d²S/dx²) = (24/x³) = (8/√3) > 0 (minimum point)
Log (5) + log (3) = log (15)
Answer:
120 <u>different</u> outfits.
Step-by-step explanation:
10x4=40
40x3=
<u>120</u>
Answer:
The probability that a student who is involved in a sports team also participated in the prom dance = 0.1344
Step-by-step explanation:
56% of the students are involved in a sport team
56% = 0.56
According to the question, it is stated that 24% of the students at the school that are involved in a sports team also participated in the prom dance.
24% = 0.24
This means that we are going to find 24% of the original 56%, since 24% of them also participated in the prom dance.
The probability that a student who is involved in a sports team also participated in the prom dance = 0.24 * 0.56
The probability that a student who is involved in a sports team also participated in the prom dance = 0.1344
