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Aneli [31]
3 years ago
7

37 \\ 5x = 4y + 5" alt="x + y = 37 \\ 5x = 4y + 5" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
murzikaleks [220]3 years ago
8 0

Answer:78

Step-by-step explanation:

I took the test

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What is the volume, in cubic centimeters, of a right rectangular prism that has a lenght of 4 centimeters, a width of 9 centimet
Temka [501]

Answer:

The volume of the prism is 360 cm^3.

Step-by-step explanation:

The rectangular prism is a three dimensional figure formed by six rectangular faces. It's volume is given by the product of it's three dimensions. The calculation for the volume of this prism is shown bellow:

volume = width*height*length

volume = 9*10*4

volume = 360 cm^3

The volume of the prism is 360 cm^3.

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Please help me with this question.​
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73

Step-by-step explanation:

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it is 4.33333 repeating

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Prove cosh 3x = 4 cosh^3 x - 3 cosh x.
Snezhnost [94]
Prove we are to prove  4(coshx)^3 - 3(coshx) we are asked to prove 4(coshx)^3 - 3(coshx) to be equal to cosh 3x
= 4(e^x+e^(-x))^3/8 - 3(e^x+e^(-x))/2 = e^3x /2 +3e^x /2 + 3e^(-x) /2 + e^(-3x) /2 - 3(e^x+e^(-x))/2 = e^(3x) /2 + e^(-3x) /2 = cosh(3x) = LHS Since y = cosh x satisfies the equation if we replace the "2" with cosh3x, we require cosh 3x = 2 for the solution to work. 
i.e. e^(3x)/2 + e^(-3x)/2 = 2 
Setting e^(3x) = u, we have u^2 + 1 - 4u = 0 
u = (4 + sqrt(12)) / 2 = 2 + sqrt(3), so x = ln((2+sqrt(3))/2) /3, Or u = (4 - sqrt(12)) / 2 = 2 - sqrt(3), so x = ln((2-sqrt(3))/2) /3, 
Therefore, y = cosh x = e^(ln((2+sqrt(3))/2) /3) /2 + e^(-ln((2+sqrt(3))/2) /3) /2 = (2+sqrt(3))^(1/3) / 2 + (-2-sqrt(3))^(1/3) to be equ
= 4(e^x+e^(-x))^3/8 - 3(e^x+e^(-x))/2 
= e^3x /2 +3e^x /2 + 3e^(-x) /2 + e^(-3x) /2 - 3(e^x+e^(-x))/2 
= e^(3x) /2 + e^(-3x) /2 
= cosh(3x) 
= LHS 

<span>Therefore, because y = cosh x satisfies the equation IF we replace the "2" with cosh3x, we require cosh 3x = 2 for the solution to work. </span>

i.e. e^(3x)/2 + e^(-3x)/2 = 2 

Setting e^(3x) = u, we have u^2 + 1 - 4u = 0 

u = (4 + sqrt(12)) / 2 = 2 + sqrt(3), so x = ln((2+sqrt(3))/2) /3, 
Or u = (4 - sqrt(12)) / 2 = 2 - sqrt(3), so x = ln((2-sqrt(3))/2) /3, 

Therefore, y = cosh x = e^(ln((2+sqrt(3))/2) /3) /2 + e^(-ln((2+sqrt(3))/2) /3) /2 
= (2+sqrt(3))^(1/3) / 2 + (-2-sqrt(3))^(1/3)
3 0
4 years ago
<img src="https://tex.z-dn.net/?f=%20-%209%20%5Ctimes%204%20%3D%20" id="TexFormula1" title=" - 9 \times 4 = " alt=" - 9 \times 4
Alika [10]

<em>Hey</em><em>!</em><em>!</em><em>!</em>

<em>Here</em><em>'s</em><em> </em><em>your</em><em> </em><em>answer</em>

<em>-</em><em>9</em><em>*</em><em>4</em><em>=</em><em>-</em><em>3</em><em>6</em>

<em>So</em><em> </em><em>the </em><em>right</em><em> </em><em>answer</em><em> </em><em>-</em><em>3</em><em>6</em><em>.</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em>

<em>G</em><em>ood</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

8 0
3 years ago
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