Differentiate it
get f ' (x)=3x^2-4
put 3x^2-4=0
x=2/√3,-2/√3
so interval
x∈(-2/√3,2/√3)
<span>We are given f(1) = 0 and f(2) = 1.
Going forward, the term is the sum of the two previous terms.
f(3) = f(2) + f(1) = 0 + 1 = 1.
f(4) = f(3) + f(2) = 1 + 1 = 2
f(5) = f(4) + f(3) = 2 + 1 = 3
This matches answer B.</span>
The range is 0 to indifinity
approx 1 foot
The area (A) of a circle = πr² ( where r is the radius)
thus r² = A/π ⇒ r = √(A/π = √(3.21/π) =1.0108..... ≈ 1 foot ( to 1 dec. place)
