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Elenna [48]
3 years ago
10

Please help :) Due asap and thx!

Mathematics
1 answer:
Elenna [48]3 years ago
8 0

Answer:

b . 6 is the length of the hypotenuse

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A county fair charges an entry fee of $7 and $0.75 for each ride token. You have $15. Write an expression that represents the am
aleksley [76]
The answer is 3.50
Because 15-7 equal 8,6 times 0.75 equal 4.50, and 8-4.5 equal 3.50
7 0
2 years ago
Read 2 more answers
Which graph represents this system?<br> 2x-5y=-5<br> y = ² x + 1<br> 5
frosja888 [35]

Answer:

x =  \frac{5(y - 1)}{2}  \\  \\ x =  \frac{y - 1}{2}

Step-by-step explanation:

2x =  - 5 + 5y \\ 2x = 5y - 5 \\ x =  \frac{5y - 5}{2}  \\  \\ y - 1 = 2x \\  \frac{y - 1}{2}  = x

7 0
2 years ago
Erwin had 2 5/12 gallons of lemonade. He spilled 11/12 gallon of lemonade. How much lemonade dose he have left? Write in simples
xz_007 [3.2K]

Answer:

Erwin have 1 \frac{1}{2}   gallons of lemonade left

Step-by-step explanation:

<u><em>Erwin had 2 5/12 gallons of lemonade. He spilled 11/12 gallon of lemonade. How much lemonade dose he have left? Write in simplest form</em></u>

<u><em /></u>

All we need to do is to subtract 11/12 from 2 5/12. But to do this, we will convert 2 5/12 to improper fraction

converting 2 5/12 to improper fraction yields : 29/12

Lemonade have left = Total lemonade - lemonade spilled

                         =          29/12 -  11/12

                               

                         =     18/12

Lemonade have left =18/12

But we can reduce 18/12 to its lowest term

18÷6/ 12÷6      =     3/2

       Lemonade have left = 3/2

We can change to 3/2 to a mixed number to give us 1 \frac{1}{2}    

Therefore Erwin have 1 \frac{1}{2}   gallons of lemonade left

6 0
3 years ago
Read 2 more answers
1. The spinner shown below is spun once. Determine the probability of
Rina8888 [55]

Answer:

1 out of 3

Step-by-step explanation:

Two desired outcomes and six total outcomes which is 2/6 simplified is 1/3

6 0
2 years ago
Write a for loop that assigns summedvalue with the sum of all odd values from 1 to usernum. assume usernum is always greater tha
Lapatulllka [165]
// Input value is usernum.
// This code snippet sums 1 + 3 + 5 + ... + usernum
//  The answer is stored in the variable summedvalue.

N = (int) (usernum+1)/2;    // maximum number of integers to be summed
int *v = malloc(N*sizeof(int));     //  allocate storage for array v

// Calculate the number of loop counts and assign array v..
count = 0;
k = 1;
while (1) {
       if (k>usernum) {   //  do not extend v beyond usernum
          break;
          }
       v(count) = k;        //  assign an odd integer to v, including usenum
       count++;
       k += 2;                //  k is an odd number
       if k>usernum {          // handle usernum as odd or even
          k = usernum;
          } 
 }
n = count;          // the size of array v.

// Calculate the sum in a for loop
summedvalue  = 0;               // initialize summedvalue
for (i=0; i<=n; i++) {
     summedvalue += v(i);
    }


5 0
3 years ago
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