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just olya [345]
2 years ago
5

Rob goes to work each day by two different routes. As he leaves the apartment parking lot there is a traffic light. If he has a

green light but not a turn arrow, he goes straight and travels for 15-20 minutes, uniformly distributed. If he has a left turn arrow, he turns left, and travels 10-15 minutes, uniformly distributed. If he has a red light, he waits for a left turn arrow. He has timed the traffic light and the light is red for 2 minutes, followed by a left turn arrow for 1 minute, and a green light for 3 minutes. He arrives at the traffic light at uniformly random times each day. What is his expected travel time?
Mathematics
1 answer:
Effectus [21]2 years ago
8 0
Can i send a pic pls help me do it ????
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A and b are positive integers and a-b=2 ... Evaluate the following:
lana [24]

Answer:

Step-by-step explanation:

a-b=2

\frac{27^{\frac{1}{3} b} }{9^{\frac{1}{2}a } } \\=\frac{(3^{3}) ^{\frac{1}{3} b} }{(3^{2} )^{\frac{1}{2} a} } \\=\frac{3^b}{3^a} \\=3^{b-a} \\=3^{-(-b+a)} \\=3^{-2}\\=\frac{1}{3^2} \\=\frac{1}{9}

5 0
2 years ago
You will be charged 10.5% interest on a loan of 678 how much interest will you pay on the loan
Y_Kistochka [10]
10.5% of 678 = 
0.105(678) = 71.19 <==
Hope this helps. 
8 0
3 years ago
Read 2 more answers
This is also seventh grade math and I need the value of X again please... 12(x+10)=24?
Gnesinka [82]

Answer: x = -8

Step-by-step explanation: To solve for <em>x</em> in this equation, our first task is to simplify the left side by distributing the 12 through both terms inside the parentheses.

When we do that, we get 12 times x which is

12x and 12 times 10 which is 120.

So we have 12x + 120 = 24.

Our next task is to isolate the x term by subtracting 120 from both sides of the equation. On the left, 120 - 120 cancels and we're left with 12x. On the right, 24 - 120 simplifies to -96 so we have 12x = -96.

To get <em>x</em> by itself, we divide both sides by 12 and <em>x = -8</em>.

Work is also attached in the image provided.

6 0
3 years ago
2. (10.03)
faust18 [17]

This question is incomplete because it was not written properly

Complete Question

A teacher gave his class two quizzes. 80% of the class passed the first quiz, but only 60% of the class passed both quizzes. What percent of those who passed the first one passed the second quiz? (2 points)

a) 20%

b) 40%

c) 60%

d) 75%

Answer:

d) 75%

Step-by-step explanation:

We would be solving this question using conditional probability.

Let us represent the percentage of those who passed the first quiz as A = 80%

and

Those who passed the first quiz as B = unknown

Those who passed the first and second quiz as A and B = 60%

The formula for conditional probability is given as

P(B|A) = P(A and B) / P(A)

Where,

P(B|A) = the percent of those who passed the first one passed the second

Hence,

P(B|A) = 60/80

= 0.75

In percent form, 0.75 × 100 = 75%

Therefore, from the calculations above, 75% of those who passed the first quiz to also passed the second quiz.

3 0
3 years ago
EASY MATH PLEASE HELP!!
blsea [12.9K]
The answer is A. If there are 3 thirds (1/3s) per yard and there are 6 yards, 3*6=18. Because the last cut will make two 1/3-yard segments, the answer is 17 cuts and not 18.
3 0
3 years ago
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