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JulijaS [17]
3 years ago
9

Which graph represents a function with a domain of all real numbers greater than or equal to -7 and less than 2?

Mathematics
1 answer:
Nesterboy [21]3 years ago
5 0

Step-by-step explanation:

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Acellus<br> 25°<br> У<br> X 120°<br> y=[ ?
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Step-by-step explanation:

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Please help me I’m super confused on this problem!
Lorico [155]

Answer:

m < amc = 54°

Step-by-step explanation:

< amb and < bmc are complementary angles whose sum equals 90°.

Therefore, to find the value of 2x°, we must first solve for x.

We can establish the following equality statement:

< amb + < bmc = < amc

< 2x° + (x + 9)° = 90°

Combine like terms:

2x° + x° + 9° = 90°

3x° + 9° = 90°

Subtract 9 from both sides:

3x° + 9° - 9° = 90° - 9°

3x = 81°

Divide both sides by 3 to solve for x:

3x/3 = 81°/3

x = 27°.

Since x = 27°, substitute its value into 2x° to find m < amc:

2x° = 2(27°) = 54°

Therefore, m < amc = 54°

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Life tests on a helicopter rotor bearing give a population mean value of 2500 hours and a population standard deviation of 135 h
stira [4]

Answer:

The percent of the parts are expected to fail before the 2100 hours is 0.15.

Step-by-step explanation:

Given :Life tests on a helicopter rotor bearing give a population mean value of 2500 hours and a population standard deviation of 135 hours.

To Find : If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?.

Solution:

We will use z score formula

z=\frac{x-\mu}{\sigma}

Mean value = \mu = 2500

Standard deviation = \sigma = 135

We are supposed to find  If the specification requires that the bearing lasts at least 2100 hours, what percent of the parts are expected to fail before the 2100 hours?

So we are supposed to find P(z<2100)

so, x = 2100

Substitute the values in the formula

z=\frac{2100-2500}{135}

z=−2.96

Now to find P(z<2100) we will use z table

At z = −2.96 the value is 0.0015

So, In percent = .0015 \times 100=0.15\%

Hence The percent of the parts are expected to fail before the 2100 hours is 0.15.

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