Well there aren’t any pictures so yea
Answer:
Given:
- Total balls = 10
- Black balls = 3
- White balls = 7
⇒ P(black ball) = 3/10 = 0.3
⇒ P(white ball) = 7/10 = 0.7
If one ball is chosen at random and <u>replaced</u>, the probabilities do not change between the first and second ball.
Let event D = first ball is black
Let event S = second ball is black
P(D) = 0.3
P(S) = 0.3 (since the first ball is replaced)
⇒ P(D ∩ S) = P(D) × P(S)
= 0.3 × 0.3
= 0.09
For Independent Events we know that: P(A ∩ B) = P(A) × P(B)
Therefore, as P(D ∩ S) = P(D) × P(S) the events are independent.
Answer:
if the numbers are separated by a fraction bar the response should be 11/12th of an hour on Saturday.
Step-by-step explanation:
1/2=6/12
5/12+6/12=11/12
