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Neporo4naja [7]
3 years ago
8

Please help me Please​

Mathematics
1 answer:
Elis [28]3 years ago
8 0

Answer:

9???

Step-by-step explanation:

6 trophies on the shelves and 3 that are not.

6 + 3 = 9

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Please answer this for me correctly. There are two questions. THANK YOU!!
Olenka [21]

Answer:

the second one is 57

the 1st is JIL

Thanks For Brainlist

5 0
2 years ago
PLZ PLZZZZ HELP ASAP!!!!! <br> Explain the error: 144x2 - 100 (12x + 10)(12x - 10) 2(6x + 5)(6x - 5)
iogann1982 [59]

9514 1404 393

Answer:

  a factor of 2 is shown, but 4 was factored out

Step-by-step explanation:

The difference of squares is factored as ...

  a² -b² = (a +b)(a -b)

Then the given difference of squares factors as ...

  144x² -100 = (12x)² -10² = (12x +10)(12x -10)

Each of these factors has a factor of 2 that can be factored out:

  = (2(6x +5))(2(6x -5))

  = (2·2)(6x +5)(6x -5)

  = 4(6x +5)(6x -5)

The first factor should be 4, not 2.

7 0
2 years ago
Is it
Hatshy [7]

Answer:

B. 90 degrees counterclockwise

Step-by-step explanation:

7 0
2 years ago
What is the answer to this problem?
Andrei [34K]

i think the best answer for this question is A)

5 0
3 years ago
Using the given information, give the vertex form equation of each parabola.
Amanda [17]

Answer:

The equation of parabola is given by : (x-4) = \frac{-1}{3}(y+3)^{2}

Step-by-step explanation:

Given that vertex and focus of parabola are

Vertex: (4,-3)

Focus:(\frac{47}{12},-3)

The general equation of parabola is given by.

(x-h)^{2} = 4p(y-k), When x-componet of focus and Vertex is same  

(x-h) = 4p(y-k)^{2}, When y-componet of focus and Vertex is same

where Vertex: (h,k)

and p is distance between vertex and focus

The distance between two points is given by :

L=\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}

For value of p:

p=\sqrt{(X2-X1)^{2}+(Y2-Y1)^{2}}

p=\sqrt{(4-\frac{47}{12})^{2}+((-3)-(-3))^{2}}

p=\sqrt{(\frac{1}{12})^{2}}

p=\frac{1}{12} and p=\frac{-1}{12}

Since, Focus is left side of the vertex,

p=\frac{-1}{12} is required value

Replacing value in general equation of parabola,

Vertex: (h,k)=(4,-3)

p=\frac{-1}{12}

(x-h) = 4p(y-k)^{2}

(x-4) = 4(\frac{-1}{12})(y+3)^{2}

(x-4) = \frac{-1}{3}(y+3)^{2}

8 0
3 years ago
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