So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
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Answer:
a^2 - 25
Step-by-step explanation:
5(a-5) turns into 5a - 25
a(a-5) turns into a^2 - 5a
added together, it's a^2 - 25
Answer:
9cm
Step-by-step explanation:
3/12 is equal to 1/4 ratio between the size of the window and the building.
Apply that ratio to the the 36 centimeters to get 36/4 which is equal to 9 centimeters.
2/5 because 10/10 minus 6/10 equals 4/10 which reduces to 2/5