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Serhud [2]
3 years ago
8

Rewrite the equation by completing the square. 4 x^{2} +20x +25 =0

Mathematics
2 answers:
Ede4ka [16]3 years ago
8 0

Answer:

(x+5/2)^2 = 0

Step-by-step explanation:

4 x^{2} +20x +25 =0

Divide by 4

4/4 x^{2} +20/4x +25/4 =0

x^2 +5x +25/4 =0

Subtract 25/4 from each side

x^2 +5x +25/4 -25/4 =-25/4

x^2 +5x  =-25/4

Take the coefficent of x

5

Divide by 2

5/2

Square it

25/4

Add it to each side

x^2 +5x +25/4 =-25/4+25/4

(x+5/2)^2 = 0

Take the square root of each side

x+5/2 = 0

x = -5/2

sukhopar [10]3 years ago
6 0

Answer:

(2x + 5)² = 0

Step-by-step explanation:

4x² + 20x + 25 = 0

4x² + 10x + 10x + 25 = 0

2x(2x + 5) + 5(2x + 5) = 0

(2x + 5)(2x + 5) = 0

(2x + 5)² = 0

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