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Sindrei [870]
2 years ago
5

This graph represents a linear function.

Mathematics
1 answer:
Alexus [3.1K]2 years ago
6 0

Answer: jjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj

Step-by-step explanation:

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Determine whether the graph represents a proportional relationship.
olya-2409 [2.1K]

No, it is not a proportional relationship because the graph does not go through the origin. A proportional relationship is supposed to be a straight line, starting from the origin. It starts on the number 4.

8 0
3 years ago
I need help again don't get it
Dmitry [639]

Answer:

x=45

Step-by-step explanation:

70+65=135

180-135=45

3 0
2 years ago
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Please help radical expression dividing
77julia77 [94]
\bf \cfrac{\sqrt[4]{63}}{4\sqrt[4]{6}}\qquad 
\begin{cases}
63=3\cdot 3\cdot 7\\
6=2\cdot 3
\end{cases}\implies \cfrac{\sqrt[4]{3\cdot 3\cdot 7}}{4\sqrt[4]{2\cdot 3}}\implies \cfrac{\underline{\sqrt[4]{3}}\cdot \sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}\cdot \underline{\sqrt[4]{3}}}
\\\\\\
\cfrac{\sqrt[4]{3}\cdot \sqrt[4]{7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{3\cdot 7}}{4\sqrt[4]{2}}\implies \cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}

\bf \textit{now, rationalizing the denominator}\\\\
\cfrac{\sqrt[4]{21}}{4\sqrt[4]{2}}\cdot \cfrac{\sqrt[4]{2^3}}{\sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21}\cdot \sqrt[4]{8}}{4\sqrt[4]{2}\cdot \sqrt[4]{2^3}}\implies \cfrac{\sqrt[4]{21\cdot 8}}{4\sqrt[4]{2\cdot 2^3}}\implies \cfrac{\sqrt[4]{168}}{4\sqrt[4]{2^4}}
\\\\\\
\cfrac{\sqrt[4]{168}}{4\cdot 2}\implies \cfrac{\sqrt[4]{168}}{8}

and is all you can simplify from it.

so... all we did, was rationaliize it, namely, "getting rid of the pesky radical at the bottom", we do so by simply multiplying it by something that will raise the radicand, to the same degree as the root, thus the radicand comes out.
6 0
3 years ago
What would be the BEST formula to model the volume of a tree trunk?
irina [24]

like a hand help model?

4 0
2 years ago
Y=x²-6x+8 what is y when x is 0?
jarptica [38.1K]

Answer:

The value of y is 8.

Step-by-step explanation:

In order to find the value of y, you have to put in x = 0 into the equation :

y =  {x}^{2}  - 6x + 8

Let x = 0,

y =  {0}^{2}  - 6(0) + 8

y = 8

6 0
3 years ago
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