Answer:
A) The value of a is <u>29</u>.
B) The value of b is <u>greater than 29</u>.
C) In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
D) The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
Step-by-step explanation:
Solving for Part A.
Given,
We have to solve for a.
By using addition property of equality, we will add both side by 9;
Hence the value of a is <u>29</u>.
Solving for Part B.
Given,
We have to solve for b.
By using addition property of inequality, we will add both side by 9;
Hence the value of b is <u>greater than 29</u>.
Solving for Part C.
In both part A and part B we have used a common property which is addition property and that we have add 9 on both side of equation in both parts.
Solving for Part D.
The value of a in part A is equal to 29 whereas in part B the value of b is greater than 29.
Answer:
The most important lab safety rule is to know the location of and how to use safety equipment, such as a fire extinguisher.
Step-by-step explanation:
Hope this helps you
Crown me as brainliest:)
I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
Answer:
The unknown value is being subtracted from 226 is 160
Step-by-step explanation:
Long division setup showing an incomplete calculation
- 2 hundreds and 1 tens is written in the quotient
- 3200 is subtracted from 3426 to give 226
- An unknown value represented by a box is being subtracted from 226
so,
The dividend = 3426
The divisor = 16
2 hundreds means 200 and 1 tens means 10
∵ The quotient = 200 + 10 + x
∵ Dividend = divisor × quotient
∴ (16 × 200) + (16 × 10) + (16 × x) +remainder = 3426
∵ 16 × 200 = 3200
Subtract 3200 from the dividend
∴ 3426 - 3200 = 226
∵ 16 × 10 = 160
∴ 226- 160 = 66
⇒160is the unknown value
∵ 16 × x = 16x
∵ 66 - 16x = 0
∴ 66 = 16x
- Divide both sides by 16
∴ x = 4 and remainder = 2
∴ 3426 ÷ 16 = 200 + 10 + 4
∴ 3426 ÷ 16 = 214
∴ From the steps above the missing number subtracted from
226 is 160
The unknown value is being subtracted from 226 is 160
7,14,21,28,35,42 ......................
