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Kitty [74]
3 years ago
10

22. I = Prt; P What do I first? It says to solve the equation for the given variable.

Mathematics
1 answer:
LuckyWell [14K]3 years ago
3 0

<em>the</em><em> </em><em>fir</em><em>st</em><em> </em><em>thing</em><em> </em><em>you</em><em> </em><em>nee</em><em>d</em><em> </em><em>to</em><em> </em><em>do</em><em> </em><em>is</em>

<em>div</em><em>ide</em><em> </em><em>the</em><em> </em><em>who</em><em>le</em><em> </em><em>equ</em><em>ation</em><em> </em><em>by </em><em>rt</em><em> </em><em>as</em><em> </em><em>sh</em><em>own</em><em> </em><em>bel</em><em>ow</em>

<em>\frac{i}{rt}  =  \frac{prt}{rt}</em>

<em>then</em><em> </em><em>you</em><em> </em><em>cance</em><em>l</em><em> </em><em>ou</em><em>t</em><em>.</em><em> </em><em>leav</em><em>ing</em>

<em>\frac{i}{rt}  = p</em>

<em>which</em><em> </em><em>is</em><em> </em><em>the</em><em> </em><em>sam</em><em>e</em><em> </em><em>as</em>

<em>p =  \frac{i}{rt}</em>

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In Mathematica, it's convenient to define a function:

P[t_] := 3t^2 + 3E^t + 10

(E is case-sensitive and must be capitalized. Alternatively, you could use Exp[t]. You can also specify that the argument t must be non-negative by entering a condition via P[t_ ;/ t >= 0], but that's not necessary.)

Then just evaluate P[1], or N[P[1]] or N <at symbol> P[1] or P[1] // N to get a numerical result.

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(P[6] - P[2])/(6 - 2)

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The approximate value is quite large, so I'll just leave its exact value.

In M, the quickest way would be P'[60], or you can differentiate and replace (via ReplaceAll or /.) t with 60 as in D[P[t], t] /. t -> 60.

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