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likoan [24]
3 years ago
12

What expressions are equivalent to 2r+(t+r)​

Mathematics
1 answer:
Eva8 [605]3 years ago
4 0

Answer:

3r + t

Step-by-step explanation:

it is that because you multiply one to t and r, and the are left with 2r + r + t. You add 2r to r and get 3r, with a left over of t.

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What is the slope of the line that passes through the points (5, 2) and (3,-1)?
oksano4ka [1.4K]
Slope = -4/5

to calculate the slope m use the gradient form

m = y2 -y1
————
x2 - x1


let (x1, y1) = (3,1) and (x2, y2) = (-2, 5)


m = 5 - 1 4
———- = ——-
-2 - 3 -5


= - 4/5
3 0
3 years ago
Help find perimeter and area
klio [65]

Answer: perimeter = 96mm, Area = 564mm².

Step-by-step explanation:

From the diagram, it is a trapezium, it has a rectangle joined together by a right angled triangle. Now to find the perimeter, we add all the dimensions together. To get the other side of the rectangle, which is also the perpendicular height of the figure, we take the Pythagoras. Let the perpendicular height = x

Therefore,

25² = ײ + 7²

625 = x² + 49

x² = 625 - 49

x² = 576

x. = √576

= 24.

Now the perimeter

= 20 + 25 + 7 + 20 + 24

= 96mm.

Area of the figure will be

= 1/2( a + b )h

Where a = 20, b = 20 + 7 = 27 and h = 24, now substitute for the values

( 20 + 27) x 24

---------------------

2

= 47 x 24/2

= 47 x 12

= 564mm²

8 0
3 years ago
The area of the rectangle as a single expression
Ne4ueva [31]

Answer: A=15x^2+6x-48

Step-by-step explanation:

The area of a rectangle can be calculated with this formula:

A=l*w

Where "l" is the length and "w" is the width.

You can identify from the figure that the length and the width of this rectangle are:

length=3(x+2)\\width=5x-8

Then, you need to substitute this lenght and this width into A=l*w:

A=3(x+2)(5x-8)

Now, apply Distributive property:

A=(3x+6)(5x-8)\\\\A=15x^2-24x+30x-48

Finally, you need to add the like terms. Then, you get:

A=15x^2+6x-48

5 0
4 years ago
Log (4x-1)+5=8<br><br> Please help me!
nordsb [41]

log (4x-1) + 5 = 8

log (4x-1) = 8 - 5

log (4x-1) = 3

4x - 1 = 10³

4x - 1 = 1000

4x = 1001

x = 1001/4

ok done. Thank to me :>

4 0
2 years ago
Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AC = 20 and DC = 5, what is the length of BC? (Note: the fi
11111nata11111 [884]

Answer:

21.2 or 15 sqrt of 2 (PETHAGOREOM theorem)

Step-by-step explanation:

a^2+b^2=c^2

20^2+5^2=C^2

400+25=C^2

450=C^2

sqrt 450=

15 sqrt of 2 or 21.2

4 0
3 years ago
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