$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{2}~,~\stackrel{y_1}{-5})\qquad B(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{6+2}{2}~~,~~\cfrac{1-5}{2} \right)\implies \left( \cfrac{8}{4}~,~\cfrac{-4}{2} \right)\implies (4,-2)$

7 0

2 years ago

Mike argues the following side lengths can make a triangle. Sam says he is incorrect. Who is correct and why? 3m, 5m, 10m

victus00 [196]

Answer:

Sam is correct

Step-by-step explanation:

The third side is the one with greatest length. To make a triangle the other two lengths have to be greater than the greatest one when combined.

Hope this Helps.

5 0

1 year ago

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