Given:
Length of first vector = 2 meters
Length of second vector = 4 meters
To find:
The vector which has a greater magnitude.
Solution:
We know that, magnitude of a vector represents the length of it.
The first vector that is 2 meters long has a magnitude 2.
The second vector that is 4 meters long has a magnitude 4.
Clearly, 4 is greater that 2, i.e., 4 > 2. So, magnitude of second vector is greater.
Therefore, the vector that is 4 meters long has greater magnitude.
Step-by-step explanation:
2) 63
3) 7000
4) 10
These are some answers
Answer:
-3 + 4sqrt(2)
-3 - 4sqrt(2)
Step-by-step explanation:
(x – 4)(x + 10) = -17
FOIL on the left hand side (First outer inner last)
x^2 +10x-4x-40 = -17
x^2 +6x-40 =-17
Add 17 to each side
x^2 +6x-40+17 =-17+17
x^2 +6x -23 = 0
Using the quadratic formula
-b + - sqrt(b^2 -4ac)
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2a
where ax^2 +bx+c=0
-6 + - sqrt(6^2 -4*1*-23)
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2*1
-6 + - sqrt(36 +92)
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2
-6 + - sqrt(128)
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2
-6 + - 8sqrt(2)
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2
Divide top and bottom by 2
-3 + - 4sqrt(2)
Answer:
x>=-12
Step-by-step explanation:
3x+7>=-29
3x>=-29-7
3x>=-36
x>=-36/3
x>=-12
