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3 years ago

Here you go the brainless

Mathematics

2 answers:

andre [41]3 years ago

5 0

Hi there!

The formula for an area A of a trapezoid with height h and bases of b1 and b2
A = h(b1+b2)/2

h= 12
b1 = 10
b2 = 15

A = 12(10+15)/2
= 6 * 25
= 150

The area is 150 ft².
Have an awesome day! :)

From your friendly Helper-in-Training, collinjun0827

lukranit [14]3 years ago

3 0

Area of trapezium
= ½(a + b)h
= ½(15 + 10)(12)
= 150 feet²

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$S1=4x^{2}-12x+9$

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$S2 = (4x-6)(3x-2)$

$S2=12x^{2}-26x+12$

Area of trapezoid S3:

$S3=\frac{(2x+3+4x+1)(2x-3)}{2}$

$S3=\frac{(6x+4)(2x-3)}{2}$

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$S=4x^{2}-12x+9+12x^{2}-26x+12-6x^{2}+5x+6$

$S=10x^{2}-33x+37$

Which is the same as S = (2x-3)(5x-9)

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$\frac{(3x-2+3x-2+2x-3)(4x-6)}{2}=\frac{(6x+4)(2x-3)}{2}$

$\frac{(8x-7)(4x-6)}{2}=\frac{(6x+4)(2x-3)}{2}$

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Using Bhaskara to solve the second degree equation:

$\frac{66+\sqrt{(-66)^{2}-(4.20.54)} }{2(20)}$

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$x_{2}=\frac{66-6}{40}$ = 1.5

For the areas of AFGC and ADEB to be equal, x has to be 1.5 or 1.8.

c) Expand a polynomial (or equation) is to multiply all the terms, remiving the parenthesis. Reduce a polynomial (or equation) is to combine terms alike,e.g.:

$S=(2x-3)(5x-9)$