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andreev551 [17]
3 years ago
9

What's is the smallest power of 10 that would exceed 999,999,999,991?

Mathematics
2 answers:
TEA [102]3 years ago
6 0
10 to the power of any number HAS to only have 1 and zeroes in it.. A number that starts with 1, ends in zeros and is greater than 999,999,999,991 is 1,000,000,000,000

1,000,000,000,000 = 10^{12}   <-answer    

(note: it has 12 zeroes)

klasskru [66]3 years ago
6 0

Answer:

The required smallest power of 10 that would exceed 999,999,999,991 is 12.

Step-by-step explanation:

Given : Number 999,999,999,991.

To find : What's is the smallest power of 10 that would exceed number ?

Solution :

Let the required power be 'x'.

According to question,

10^x=999,999,999,991

Taking log both side,

\log (10^x)=\log(999,999,999,991)

Apply logarithmic property, \log a^x=x\log a

x\log (10)=\log(999,999,999,991)

x=\log(999,999,999,991)

Using calculator,

x=12

Therefore, The required smallest power of 10 that would exceed 999,999,999,991 is 12.

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