Question

What's is the smallest power of 10 that would exceed 999,999,999,991?

Answer 1

10 to the power of any number HAS to only have 1 and zeroes in it.. A number that starts with 1, ends in zeros and is greater than 999,999,999,991 is 1,000,000,000,000

1,000,000,000,000 = $10^{12}$   <-answer    

(note: it has 12 zeroes)

Answer 2

Answer:

The required smallest power of 10 that would exceed 999,999,999,991 is 12.

Step-by-step explanation:

Given : Number 999,999,999,991.

To find : What's is the smallest power of 10 that would exceed number ?

Solution :

Let the required power be 'x'.

According to question,

$10^x=999,999,999,991$

Taking log both side,

$\log (10^x)=\log(999,999,999,991)$

Apply logarithmic property, $\log a^x=x\log a$

$x\log (10)=\log(999,999,999,991)$

$x=\log(999,999,999,991)$

Using calculator,

$x=12$

Therefore, The required smallest power of 10 that would exceed 999,999,999,991 is 12.