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Cerrena [4.2K]
3 years ago
7

The complex polygon below represents the layout of a parking lot. Find the area of the parking lot in square meters.

Mathematics
1 answer:
alukav5142 [94]3 years ago
8 0

Answer:

The area of the parking lot is: 144cm^2

Step-by-step explanation:

Given

See attachment for polygon

Required

The area of the parking lot

The attached plot has 6 congruent triangles with the following dimension;

Base = 6cm

Height = 8cm

Area = \frac{1}{2} * Base * Height

Area = \frac{1}{2} * 6cm * 8cm

Area = 24cm^2

The area of the 6 triangles is:

Area = 6 * Area of 1 triangle

Area = 6 * 24cm^2

Area = 144cm^2

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Answer:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}

Step-by-step explanation:

<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}

Operating on the numerators:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}

Removing parentheses:

\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}

Simplifying:

\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}

The expression cannot be further simplified.

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Hi, since the situation forms a right triangle (see image attached) the angle formed between his home and the library is 90°.

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