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3 years ago

BEST ANSWER GETS TO BE BRANILYEST!!!!!

Mathematics

1 answer:

tiny-mole [99]3 years ago

7 0

The correct answer would be choice
D
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Farmer brown had ducks and horses one day he noticed that all of the Animals had a total of 12 heads and 32 feet how many animal

brilliants [131]

Answer:

4 horses and 8 ducks.

Step-by-step explanation:

Let the number of ducks be d and the number of horses be h.

d + h = 12

Now ducks have 2 feet and horses have 4 so:

2d + 4h = 32

Multiply the first equation by 2

2d + 2h = 24

Subtract this equation from the second equation:

4h - 2h = 32 - 24

2h = 8

h = 4.

So there were 4 horses and 12 - 4 = 8 ducks.

4 0

3 years ago

Drew wrote three equations.

viva [34]

Answer:

Step-by-step explanation:

4*8=32

7*8=56

8*8=64

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3 years ago

The histogram displays the tree growth in one year for a sample of trees measured at Shady Farms.

s344n2d4d5 [400]

Answer:

1.48 2.100

Step-by-step explanation:

4 0

3 years ago

2x-3y=5.5 What is the solution to the system of equations shown above

sasho [114]

Answer:

⸻⸻⸻⸻⸻

Solving

2X + 3Y = 5.5

⸻⸻⸻⸻⸻

Simplifying

2X + 3Y = 5.5

⸻⸻⸻⸻⸻

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

⸻⸻⸻⸻⸻

Add -3y to each side of the equation.

2x + 3y + -3y = 5.5 + -3y

⸻⸻⸻⸻⸻

Combine terms: 3y + -3y = 0.

2x + 0 = 5.5 + -3y

2x = 5.5 + -3y

⸻⸻⸻⸻⸻

Divide each side by 2.

x = 2.75 + -1.5y

⸻⸻⸻⸻⸻

Simplifying.

x = 2.75 + -1.5y

⸻⸻⸻⸻⸻

5 0

3 years ago

Applying Properties of Exponents In Exercise,use the properties of exponents to simplify the expression.

Eduardwww [97]

Answer:

$1. ~e^5\\2. ~e^{\frac{3}{2}}\\3. ~e^6\\4.~ e^7$

Step-by-step explanation:

We have to simplify the given exponential expressions

Exponential properties:

$e^0 =1\\e^a.e^b = e^{a+b}\\\\\displaystyle\frac{e^a}{e^b} = e^{a-b}\\\\(e^a)^b = e^{ab\\\\e^{-a} = \frac{1}{e^a}$

Simplification takes place in the following manner:

$(e^2)^\frac{5}{2}\\\text{Applying the exponential property}\\\\=e^{2\times \frac{5}{2}}\\= e^5$

$(e^2)(e^{\frac{1}{2}})\\\text{Using the exponential propert}\\\\= e^{2 + \frac{1}{2}} = e^{\frac{3}{2}}$

$(e^{-2})^{-3}\\= e^{-2\times -3}\\=e^6$

$\displaystyle\frac{e^5}{e^{-2}}\\\\\text{Using exponential properties}\\\\= e^{5-(-2)} = e^7$

4 0

4 years ago